试图通过android连接到wsdl Web服务

Question

我想连接到基于WSDL的Web服务，只需在TextView中显示String响应

代码：

package com.example.wsdlclient;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;

import android.util.Log;
import android.widget.TextView;
import android.app.Activity;
import android.os.Bundle;

public class MainActivity extends Activity {

    private static final String SOAP_ACTION = "http://www.taryatechnologies.com/ws/getCountry";
    private static final String METHOD_NAME = "getCountry";
    private static final String NAMESPACE = "http://www.taryatechnologies.com/ws";
    private static final String URL = "http://tarya.co.uk/ws/Ip2countryws.asmx?WSDL";

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Thread networkThread = new Thread() {
            @Override
            public void run() {
                try {

                    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
                    request.addProperty("arg0", "49.248.145.220");

                    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                            SoapEnvelope.VER11);


                    envelope.setOutputSoapObject(request);


                    HttpTransportSE ht = new HttpTransportSE(URL);

                    ht.call(SOAP_ACTION, envelope);

                    final SoapPrimitive response = (SoapPrimitive) envelope.getResponse();

                    final String str = response.toString();

                    runOnUiThread(new Runnable() {

                            public void run() {

                            TextView result;
                            result = (TextView)  findViewById(R.id.textView1);
                            result.setText(str);
                        }
                    });

                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        };
        networkThread.start();
    }
}

该服务应该返回IP所属的国家/地区名称。 我通过请求传递了IP：

  

request.addProperty（“arg0”，“49.248.145.220”）;

也尝试过：

  

request.addProperty（“ipnumb”，“49.248.145.220”）;             //因为ipnumb是参数ID。

我得到以下字符串（错误）作为回复：

  

从字符串“”到“Double”类型的转换无效。

请帮忙。