Question

我有一个奇怪的问题。当我尝试使用Time-picker选择时间时，我得到一个奇怪的结果。

例如，如果我将时间设置为11:04，则输出为11:4 ???

此外，如果我将时间设置为12:30，则输出为12:3 ???

//Time Picker Dialog
protected Dialog onCreateDialog(int id)
{
    switch(id)
    {
    case dialog_id:
        return new TimePickerDialog(this, mTimeSetListener, hour, minute, false);
    }       
    return null;
}

private TimePickerDialog.OnTimeSetListener mTimeSetListener = new TimePickerDialog.OnTimeSetListener() {

    @Override
    public void onTimeSet(TimePicker view, int hourOfDay, int hour_minute) 
    {
        hour = hourOfDay;
        minute = hour_minute;

        if (hourOfDay > 12) 
        {
            hour = hourOfDay - 12;
            amORpm = "PM";
        } 
        else 
        {
            hour = hourOfDay;
            amORpm = "AM";
        }

        textBox.setText(hour + " : " + minute + " " + amORpm);

        Toast.makeText(getBaseContext(), "Arrival time changed to: " + hour +":" + minute , Toast.LENGTH_LONG).show();

    }
};

Answer 1

尝试使用

minute = String.valueOf(hour_minute);

因为Integer省略了起始0，并确保分钟是字符串变量

Answer 2

您需要使用以下格式正确显示一位数字时间：

String.format("%02d:%02d", hour, min);

其中小时和分钟表示小时和分钟的值。

Answer 3

由于返回值是整数，因此排除前导零。如果你需要使用整数，比如设置闹钟，你就可以这样做。要显示给用户，您可以从日历中获取时间作为字符串，并将其存储在一个字符串中，该字符串将具有前导零，如02:05。得到这样的结果将返回值为零，但作为字符串：

String.format("%02d", minute);

Answer 4

使用下面的代码，它对我来说非常合适。

@Override
    protected Dialog onCreateDialog(int id) {
        switch (id) {
        case TIME_DIALOG_ID:
            // set time picker as current time
            return new TimePickerDialog(this, timePickerListener, hour,
                    minute, false);
        }
        return null;
    }

    private TimePickerDialog.OnTimeSetListener timePickerListener = new TimePickerDialog.OnTimeSetListener() {
        @Override
        public void onTimeSet(TimePicker view, int hourOfDay, int minutes) {
            hour = hourOfDay;
            minute = minutes;
            updateTime(hour, minute);
        }
    };

    private void updateTime(int hours, int mins) {

        String timeSet = "";
        if (hours > 12) {
            hours -= 12;
            timeSet = "PM";
        } else if (hours == 0) {
            hours += 12;
            timeSet = "AM";
        } else if (hours == 12)
            timeSet = "PM";
        else
            timeSet = "AM";

        String minutes = "";
        if (mins < 10)
            minutes = "0" + mins;
        else
            minutes = String.valueOf(mins);

        String aTime = new StringBuilder().append(hours).append(':').append(minutes)
                .append(" ").append(timeSet).toString();
            textBox.setText(aTime);
    }

Answer 5

使用此课程

public class TimeListener implements OnClickListener, OnTimeSetListener {

    private int hour;
    private int minute;
    private Activity activity;
    private View touchedView;

    public TimeListener(Activity activity) {
        this.activity = activity;
        final Calendar c = Calendar.getInstance();
        this.hour = c.get(Calendar.HOUR_OF_DAY);
        this.minute = c.get(Calendar.MINUTE);
    }

    public int getHour() {
        return hour;
    }

    public int getMinute() {
        return minute;
    }


    @Override
    public void onClick(View v) {
        touchedView = v;

        new TimePickerDialog(activity,
                this, this.getHour(), this.getMinute(), false).show();
    }

    private void updateDisplay() {
        ((TextView) touchedView).setText(
            new StringBuilder()
                    .append(pad(hour)).append(":")
                    .append(pad(minute)));
    }

    private static String pad(int c) {
        if (c >= 10)
            return String.valueOf(c);
        else
            return "0" + String.valueOf(c);
    }

    public void onTimeSet(TimePicker view, int hourOfDay, int minute) {
        this.hour = hourOfDay;
        this.minute = minute;
        updateDisplay();
    }
}

并使用下面的代码在您的活动类中......

private TimeListener timeListener = new TimeListener(this);
view.setOnClicklistner(timeListener);

谢谢...

时间戳显示时间不正确

5 个答案: