如何从XML文件更新SQL数据库表?

时间:2014-01-31 07:50:58

标签: sql xml database sql-update

我发现一个XML文件在每日基础(在网络上)上更新,我想从这个文件中的数据创建一个数据库表,并且可以选择更新它,任何帮助?

我正在使用Microsoft Visual Web developer 2010,我该怎么办?

1 个答案:

答案 0 :(得分:2)

我会将它存储在一个表中,如下所示(使用您选择的主键,我猜测代理身份列或货币代码和最后更新的复合键):

CREATE TABLE dbo.Currency
(   
    LastUpdate DATE NOT NULL,
    CurrencyCode CHAR(3) NOT NULL,
    Name NVARCHAR(10) NOT NULL,
    Unit INT NOT NULL,
    Country NVARCHAR(50) NOT NULL,
    Rate DECIMAL(10, 4) NOT NULL,
    Change DECIMAL(10, 4) NOT NULL
);

然后,您可以使用存储过程保存文件,并使用XQuery

查询XML
CREATE PROCEDURE dbo.SaveCurrencyXML @XML XML
AS

    INSERT dbo.Currency (LastUpdate, CurrencyCode, Name, Unit, Country, Rate, Change)
    SELECT  LastUpdate = @XML.value('CURRENCIES[1]/LAST_UPDATE[1]', 'DATE'),
            CurrencyCode = Currency.value('CURRENCYCODE[1]', 'CHAR(3)'),
            Name = Currency.value('NAME[1]', 'NVARCHAR(50)'),
            Unit = Currency.value('UNIT[1]', 'INT'),
            Country = Currency.value('COUNTRY[1]', 'NVARCHAR(50)'),
            Rate = Currency.value('RATE[1]', 'DECIMAL(10, 4)'),
            Change = Currency.value('CHANGE[1]', 'DECIMAL(10, 4)')
    FROM    @XML.nodes('CURRENCIES/CURRENCY') c (Currency);
    GO

虽然如果使用复合键,则需要使用MERGE:

CREATE PROCEDURE dbo.SaveCurrencyXMLMERGE @XML XML
AS
    WITH C AS
    (   SELECT  LastUpdate = @XML.value('CURRENCIES[1]/LAST_UPDATE[1]', 'DATE'),
                CurrencyCode = Currency.value('CURRENCYCODE[1]', 'CHAR(3)'),
                Name = Currency.value('NAME[1]', 'NVARCHAR(50)'),
                Unit = Currency.value('UNIT[1]', 'INT'),
                Country = Currency.value('COUNTRY[1]', 'NVARCHAR(50)'),
                Rate = Currency.value('RATE[1]', 'DECIMAL(10, 4)'),
                Change = Currency.value('CHANGE[1]', 'DECIMAL(10, 4)')
        FROM    @XML.nodes('CURRENCIES/CURRENCY') c (Currency)
    )
    MERGE dbo.Currency cu
    USING C 
        ON C.LastUpdate = cu.LastUpdate
        AND C.CurrencyCode = cu.CurrencyCode
    WHEN MATCHED AND 
                C.Name != cu.Name 
            OR  C.Unit != cu.Unit
            OR  C.Country != cu.Country
            OR  C.Rate != cu.Rate
            OR  C.Change != cu.Change
        THEN UPDATE
        SET Name = C.Name,
            Unit = C.Unit,
            Country = C.Country,
            Rate = C.Rate,
            Change = C.Change
    WHEN NOT MATCHED THEN
        INSERT (LastUpdate, CurrencyCode, Name, Unit, Country, Rate, Change)
        VALUES (C.LastUpdate, C.CurrencyCode, C.Name, C.Unit, C.Country, C.Rate, C.Change);

然后,您只需调用您的程序来保存数据:

DECLARE @X XML = '<CURRENCIES>
                    <LAST_UPDATE>2014-01-30</LAST_UPDATE>
                    <CURRENCY><NAME>Dollar</NAME><UNIT>1</UNIT><CURRENCYCODE>USD</CURRENCYCODE><COUNTRY>USA</COUNTRY><RATE>3.492</RATE><CHANGE>0.057</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Pound</NAME><UNIT>1</UNIT><CURRENCYCODE>GBP</CURRENCYCODE><COUNTRY>Great Britain</COUNTRY><RATE>5.7575</RATE><CHANGE>-0.312</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Yen</NAME><UNIT>100</UNIT><CURRENCYCODE>JPY</CURRENCYCODE><COUNTRY>Japan</COUNTRY><RATE>3.4087</RATE><CHANGE>0.383</CHANGE></CURRENCY><CURRENCY><NAME>Euro</NAME><UNIT>1</UNIT><CURRENCYCODE>EUR</CURRENCYCODE><COUNTRY>EMU</COUNTRY><RATE>4.7492</RATE><CHANGE>-0.204</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Dollar</NAME><UNIT>1</UNIT><CURRENCYCODE>AUD</CURRENCYCODE><COUNTRY>Australia</COUNTRY><RATE>3.0620</RATE><CHANGE>0.219</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Dollar</NAME><UNIT>1</UNIT><CURRENCYCODE>CAD</CURRENCYCODE><COUNTRY>Canada</COUNTRY><RATE>3.1225</RATE><CHANGE>-0.24</CHANGE></CURRENCY>
                    <CURRENCY><NAME>krone</NAME><UNIT>1</UNIT><CURRENCYCODE>DKK</CURRENCYCODE><COUNTRY>Denmark</COUNTRY><RATE>0.6365</RATE><CHANGE>-0.188</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Krone</NAME><UNIT>1</UNIT><CURRENCYCODE>NOK</CURRENCYCODE><COUNTRY>Norway</COUNTRY><RATE>0.5602</RATE><CHANGE>-0.568</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Rand</NAME><UNIT>1</UNIT><CURRENCYCODE>ZAR</CURRENCYCODE><COUNTRY>South Africa</COUNTRY><RATE>0.3099</RATE><CHANGE>-1.054</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Krona</NAME><UNIT>1</UNIT><CURRENCYCODE>SEK</CURRENCYCODE><COUNTRY>Sweden</COUNTRY><RATE>0.5378</RATE><CHANGE>-0.407</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Franc</NAME><UNIT>1</UNIT><CURRENCYCODE>CHF</CURRENCYCODE><COUNTRY>Switzerland</COUNTRY><RATE>3.8827</RATE><CHANGE>0.072</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Dinar</NAME><UNIT>1</UNIT><CURRENCYCODE>JOD</CURRENCYCODE><COUNTRY>Jordan</COUNTRY><RATE>4.9370</RATE><CHANGE>0.032</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Pound</NAME><UNIT>10</UNIT><CURRENCYCODE>LBP</CURRENCYCODE><COUNTRY>Lebanon</COUNTRY><RATE>0.0232</RATE><CHANGE>0</CHANGE></CURRENCY>
                    <CURRENCY><NAME>Pound</NAME><UNIT>1</UNIT><CURRENCYCODE>EGP</CURRENCYCODE><COUNTRY>Egypt</COUNTRY><RATE>0.5016</RATE><CHANGE>0.06</CHANGE></CURRENCY>
                </CURRENCIES>';

EXECUTE dbo.SaveCurrencyXML @X;

<强> Example on SQL Fiddle


<强>附录

我假设当你说你插入时:

Insert into History values('{0}','{1}','{2}','{3}','{4}')", date, id, "Deposit", amount, curr

您实际上正在使用String.Format,即:

var sql = String.Format("Insert into History values('{0}','{1}','{2}','{3}','{4}')", date, id, "Deposit", amount, curr);

如果是这样请立即停止。这是非常糟糕的做法,它不仅让你对SQL injection有所帮助,而且每次都会强制重新编译查询,因为它无法使用cached query plans。 另一个缺点是它没有强类型,在您的查询中,假设date属于DateTime类型,您自动调用此ToString()方法,这将返回依赖于的字符串调用它的线程的文化信息,不能保证输出字符串将采用数据库识别为日期时间的格式,因此如果您的目标列是日期时间,则会出现转换错误。

相反,你应该使用参数化查询,但首先,虽然我怀疑你也可能为了示例目的缩短了查询,但插入时explicitly state the column list总是一个好主意,所以你的最终查询将变成:

var sql = "INSERT History (Date, Id, Deposit, Amount, Curr) VALUES (@Date, @Id, @Deposit, @Amount, @Curr);";

然后,您需要将参数添加到SqlCommand,例如

var date = DateTime.Now;
command.Parameters.AddWithValue("@Date", date);

这意味着当发送到数据库时,查询会将@Date视为DateTime(因为传递的值是日期时间),这意味着您的查询更加类型安全。

因此,对于您的示例,要调用上面的存储过程,您将使用以下内容:

//using System.Xml;
//using System.Data.SqlClient;
//using System.Data.SqlTypes;

XmlDocument xmldoc = new XmlDocument();
xmldoc.Load(@"YourXMLFile.xml");
using (var connection = new SqlConnection("ConnectionString"))
using (var command = new SqlCommand("dbo.SaveCurrencyXML", connection))
{
    var xml = new SqlXml(new XmlTextReader(xmldoc.InnerXml, XmlNodeType.Document, null));
    var param = new SqlParameter("@XML", SqlDbType.Xml).Value = xml;
    command.Parameters.Add(param);
    command.ExecuteNonQuery();
}