Question

目前，当我将查询字符串传递给$ location的search（）方法时，我的查询字符串是uri编码的

实施例

$location.path('/some_path').search({'ids[]': 1})

变为

http://some_url/some_path?ids%5B%5D=1

我想知道是否有办法解决这个问题？

Answer 1

问题是.search（）使用在内部使用encodeURIComponent和this function的encodeUriQuery转义除以下字符之外的所有字符：字母，十进制数字， - _。！〜*'（）

Angular source code中的当前函数：

/**
 * This method is intended for encoding *key* or *value* parts of query component. We need a custom
 * method because encodeURIComponent is too aggressive and encodes stuff that doesn't have to be
 * encoded per http://tools.ietf.org/html/rfc3986:
 *    query       = *( pchar / "/" / "?" )
 *    pchar         = unreserved / pct-encoded / sub-delims / ":" / "@"
 *    unreserved    = ALPHA / DIGIT / "-" / "." / "_" / "~"
 *    pct-encoded   = "%" HEXDIG HEXDIG
 *    sub-delims    = "!" / "$" / "&" / "'" / "(" / ")"
 *                     / "*" / "+" / "," / ";" / "="
 */
function encodeUriQuery(val, pctEncodeSpaces) {
  return encodeURIComponent(val).
             replace(/%40/gi, '@').
             replace(/%3A/gi, ':').
             replace(/%24/g, '$').
             replace(/%2C/gi, ',').
             replace(/%20/g, (pctEncodeSpaces ? '%20' : '+'));
}

如果该函数有这个额外的替换，则括号将保持未编码：

replace(/%5B/gi, '[').
replace(/%5D/gi, ']').

防止AngularJS路由中的url编码

1 个答案: