Question

您好我正在使用android。我创建了一个Android应用程序，它将文件上传到服务器。我使用了以下代码

http://androidexample.com/Upload_File_To_Server_-_Android_Example/index.php?view=article_discription&aid=83&aaid=106

但我无法上传文件。该应用程序显示已开始上传，但没有文件上传到我的服务器位置。

Answer 1

public class save扩展了AsyncTask { 私人MyProgressDialog pDialog;

    @Override
    protected void onPreExecute() {
        pDialog = new MyProgressDialog(Send_message.this);
        pDialog.setCancelable(false);
        pDialog.show();
        super.onPreExecute();
    }

    @Override
    protected String doInBackground(String... paramss) {
        try {
            String json = messagesend.sendmeesage("Your Url",params);
            JSONObject jsonobject = new JSONObject(json);
            String result = jsonobject.getString("result");
            if (result.equals("TRUE")) {
                return "true";
            }

            System.out.println("json is" + json);
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } catch (JSONException e) {
            e.printStackTrace();
        }
        return "false";
    }

    @Override
    protected void onPostExecute(String result) {
        super.onPostExecute(result);
        pDialog.dismiss();
    }

}

//用于发送文件公共类messagesendwithhttp {

private String page;

public String sendmeesage(String url, List<NameValuePair> nameValuePairs)throws ClientProtocolException, IOException 
{
    HttpClient httpClient = new DefaultHttpClient();
    HttpContext localContext = new BasicHttpContext();
    HttpPost httpPost = new HttpPost(url);

    try {
        MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);

        for (int index = 0; index < nameValuePairs.size(); index++) 
        {
            if (index == 0 || index == 1) 
            {
                // If the key equals to "image", we use FileBody to transfer
                // the data
                entity.addPart(nameValuePairs.get(index).getName(), new StringBody(nameValuePairs.get(index).getValue()));
            } else {
                // Normal string data
                if(nameValuePairs.get(index).getValue().equals("") || nameValuePairs.get(index).getValue().toString().equals(null))
                {
                    entity.addPart(
                            nameValuePairs.get(index).getName(),
                            new StringBody(nameValuePairs.get(index).getValue()));
                }
                else
                {
                    entity.addPart(nameValuePairs.get(index).getName(),
                        new FileBody(new File(nameValuePairs.get(index)
                                .getValue())));
                }

            }
        }


        httpPost.setEntity(entity);
        HttpResponse response = httpClient.execute(httpPost, localContext);
        HttpEntity resEntity = response.getEntity();
        if (resEntity != null) 
        {
            page = EntityUtils.toString(resEntity);
            System.out.println("PAGE :" + page);
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
    return page;
}

}

enter code here

Answer 2

你可以使用httpmime库上传任何文件（图像，音频，视频等..）请参考下面的代码。

enter code here


    HttpClient httpClient = new DefaultHttpClient();
    HttpContext localContext = new BasicHttpContext();
    HttpPost postRequest = new HttpPost(your url);
    MultipartEntity reqEntity = new MultipartEntity(
            HttpMultipartMode.BROWSER_COMPATIBLE);

    try {




        File file = new File(filename);
        FileBody fileBody = new FileBody(file);
        reqEntity.addPart("video_file", fileBody);

        postRequest.setEntity(reqEntity);
        HttpResponse response = httpClient.execute(postRequest,
                localContext);
        HttpEntity entity = response.getEntity();

        if (entity != null) {
            // entity.consumeContent();
            BufferedReader rd = new BufferedReader(new InputStreamReader(
                    entity.getContent()));
            // Log.e("response", "response " + rd.toString());
            String line;
            String result1 = "";
            while ((line = rd.readLine()) != null) {
                result1 = result1 + line;
                // Log.e("result", "line  " + line);




    }
            // Log.e("result", "is   " + result1);
            return result1;
        }
    } catch (Exception e) {
        return "Exception";
    }
    return "";
}

}

Answer 3

她是文件上传到服务器程序的Drop box链接 https://www.dropbox.com/s/qasj5o5mu3dq5ya/file_remote_send.zip 你只需改变Bellow Code

您的服务器的URl放在这里 String upLoadServerUri =“http://example.com/UploadToServer.php&#8221 ;;

这里uploaded_file id php base filename conn.setRequestProperty（“uploaded_file”，fileName）;

UploadToServer.php

<?php

$file_path = “uploads/”;

$file_path = $file_path . basename( $_FILES['uploaded_file']['name']);
if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $file_path)) {
echo “success”;
} else{
echo “fail”;
}
?>

Answer 4

     private class SendHttpRequestTask extends AsyncTask<String, Void, String> {

        protected String doInBackground(String... params) {

           String url = params[0];

          String param1 = params[1];

          String param2 = params[2];

         Bitmap b = BitmapFactory.decodeResource(UploadActivity.this.getResources(), R.drawable.logo);



        ByteArrayOutputStream baos = new ByteArrayOutputStream();

        b.compress(CompressFormat.PNG, 0, baos);



        try {

             HttpClient client = new HttpClient(url);

             client.connectForMultipart();

             client.addFormPart("param1", param1);

             client.addFormPart("param2", param2);

             client.addFilePart("file", "logo.png", baos.toByteArray());

             client.finishMultipart();

              String data = client.getResponse();

         }

          catch(Throwable t) {

           t.printStackTrace();

       }



        return null;

     }



    @Override

      protected void onPostExecute(String data) {           

       item.setActionView(null);



       }



     }

Android fileupload无法正常工作

4 个答案: