Question

我的网页上有这个代码。它显示了推荐信。但是我得到了Uncaught TypeError的奇怪错误：对象[object Object]的属性'$'不是函数。

关于堆栈溢出的一些类似问题建议使用jQuery而不是$，但即便在那里工作。

代码是这个

<script src="./Aero Travel & Tours_files/jquery-1.9.0.min.js" type="text/javascript" charset="utf-8"></script>


<script type="text/javascript" src="./Aero Travel & Tours_files/jquery.bxslider.min.js"></script>
<script> 


var bx= $.noConflict(true);

    bx(document).ready(function() {
bx('.testimonials-slider').bxSlider({
        slideWidth: 800,
        minSlides: 1,
        maxSlides: 1,
        slideMargin: 32,
        auto: true,
        autoControls: true
      })});




 $(document).ready(function () {

$.ajax({
    type: "POST",
    url: "/Web/Common/API/WebService1.asmx/GetTestimonials",
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    async: true,
    success: function (data) {
        var json = $.parseJSON(data.d)
        var testimonial = "";
        $.each(json, function (i, obj) {
            if (i == 0 || i + 1 == json.length) {
                testimonial += "<div class='slide bx-clone'>";
            }
            else {
                testimonial += "<div class='slide'>";
            }
            testimonial += "   <div class='testimonials-carousel-context'>";
            testimonial += "      <div class='testimonials-name' style='font-weight: bold;'>" + obj.Signature + "</div>";
            testimonial += "      <div class='testimonials-carousel-content'>" + obj.Description + "</div>";
            testimonial += "   </div>";
            testimonial += "</div>";
            testimonial += "<br/>";
        });
        $('#testimonials').html(testimonial);
    }, //success
    error: function (jqXHR, testStatus, errorThrown) {
        alert("The following error occured while retrieving the project information: " + testStatus + " " + errorThrown);
    } //error
});
});
</script>

Answer 1

如果只是冲突问题，请尝试更改document.ready函数，如下所示：

jQuery(document).ready(function($) {
  // inside you can now use the $ as before.

});

Answer 2

var bx= $.noConflict(true);

在您的代码

中，

'$'符号应替换为'bx'

使用ajax时出现jquery冲突问题

2 个答案: