错误说，“语句无法解析重载函数的地址”

Question

我是初学程序员，所以这看起来很混乱，但我一直在解决标题中提到的问题。无论我在哪里尝试endl;它一直给我同样的错误。此外，当我运行代码时，我对第二个商店的总数是正确的，但第一个商店总数没有。有关如何解决此问题的任何想法？我在Windows 7计算机上使用代码块。

#include <iostream> //Allows cout/cin
#include <ctime> //Allows time
#include <iomanip> //Allows setprecision

using namespace std;

int main()
{
    //Include header

    //Input variables
    double widgetStores;
    double numberSoldFirst1;
    double numberSoldFirst2;
    double numberSoldSecond1;
    double numberSoldSecond2;
    double widgetsLeftS1W2;
    double widgetsLeftS2W1;
    double widgetsLeftS2W2;

    //Start Clock
    clock_t begin, end;
    double time_spent;
    begin = clock();

    //Prompt for total number in stores

    cout << "Total number of widgets at each store starting with :";
    cin >> widgetStores;

    double widgetStore1=widgetStores;
    double widgetStore2=widgetStores;
    double widgetsLeftS1W1;


    //Prompt for amount sold during first and second week

    cout << "How many widgets were sold at Store 1 the first week? ";
    cin >> numberSoldFirst1;
    cout << "How many widgets were sold at Store 1 the 2nd week? ";
    cin >> numberSoldSecond1;
    cout << "How many widgets were sold at Store 2 the first week? ";
    cin >> numberSoldFirst2;
    cout << "How many widgets were sold at Store 2 the 2nd week? ";
    cin >> numberSoldSecond2;

    //Calculate Number of widgets
    widgetsLeftS1W1-=(widgetStore1-numberSoldFirst1);
    widgetsLeftS1W2-=(numberSoldFirst1-numberSoldSecond1);
    widgetsLeftS2W1-=(widgetStore2-numberSoldFirst2);
    widgetsLeftS2W2-=(numberSoldFirst2-numberSoldSecond2);

    //Display Values
    cout << "Store 1 has " << widgetsLeftS1W2 << " widgets left after the 2nd week.";
    cout << "Store 2 has " <<widgetsLeftS2W2 << " widgets left after the 2nd week.";

    //Show time elapsed
    end = clock();
    time_spent = (double)(end - begin) / CLOCKS_PER_SEC;
    cout << setprecision(2) << fixed << "****Elapsed time:" <<time_spent/60 <<        "minutes****";
    return 0;

Answer 1

你有没有试过像

这样的东西

cout << "Total number of widgets at each store starting with :";
cin >> widgetStores;
cout << endl; //Added this

cin没有＆lt;＆lt;运算符，所以你需要将它发送给cout。

编辑：我发现了您遇到的错误。我想你正试图按字面意思插入行

  

ENDL;

这不会去任何地方......

Answer 2

此程序唯一的编译错误是您在初始化之前使用widgetsLeftS1W1，widgetsLeftS1W2，widgetsLeftS2W1和widgetsLeftS2W2。

您可能需要=而不是-=。

当你说

时

widgetsLeftS1W1 -= (widgetStore1-numberSoldFirst1);

你的意思是

widgetsLeftS1W1 = widgetsLeftS1W1 - (widgetStore1-numberSoldFirst1);

计算机不知道 widgetsLeftS1W1 的值，因此它会给您错误。

---

结论：使用

widgetsLeftS1W1 = (widgetStore1 - numberSoldFirst1); 

Answer 3

尝试初始化

的值

widgetsLeftS1W1
widgetsLeftS1W2
widgetsLeftS2W1
widgetsLeftS2W2

在将它们声明为顶部时为零。