Question

我有一个带两个ChoiceFields的Django表单。我将它们称为CF1和CF2。现在，CF1显示汽车模型列表。 CF2保持空白，直到在CF1中选择了一个选择，然后我的JQuery接管CF2并使用该车型的品牌填充。示例：日产 - ＆gt;千里马。

from django import forms

cars = (('', '----'), ('1', 'Toyota'), ('2', 'Nissan'), ('3', 'Ford'), ('4', 'Honda'))

class SearchForm(forms.Form)
     model = forms.ChoiceField(choices=cars required=True)
     make = forms.ChoiceField(required=True) 

     def clean(self):
         cleaned_data = super(SearchForm, self).clean()
         mo = cleaned_data.get("model")
         ma = cleaned_data.get("make")

         if not mo or not ma:
             raise forms.ValidationError("blahblah")
         return cleaned_data

只有用户在两个ChoiceFields中进行选择时，才应将表单视为有效。但是，无论是否将选择留空，我提交的表单始终无效。现在，我知道对于ChoiceField，总有一个默认的初始值，对吗？但有没有办法将ChoiceField的有效标志设置为无效，直到选择了某个标志切换为有效的位置为止？

view.py

def car_info(request): form = SearchForm(request.GET) # a form bound to the GET data if form.is_valid(): # never seems to be pass this test return render(request, "car.html", {}) else: # always ends up here form = SearchForm() # an unbound form return render(request, "find.html", {'form': form})

find.html

{% if form.errors %} <div class="err">{{ form.errors | pluralize }}</div> {% endif %} <form action="{% url "msite.views.car_info" %}" method="GET" name="listform"> {{ form.model }} {{ form.make }} <button>Find</button> </form>

Answer 1

您的代码中存在一些错误：

class SearchForm(forms.Form)
     model = forms.ChoiceField(choices=cars required=True)
     make = forms.ChoiceField(required=True)

更改为：

class SearchForm(forms.Form)
     model = forms.CharField(max_length=20, choices=cars, default=cars[0][0])
     # add other code if you like

我将Django表单的ChoiceField的初始值设置为无效是什么值？

1 个答案: