Question

有人可以帮忙计算这个PIVOT表底部的总行吗？

    select *, [Drug1] + [Drug2] + [Drug3] + [Drug4] + [Drug5] as [Total]
from 
        (Select [id], [drug], [Diagnosis]
            from DrugDiagnosis
        ) as ptp
        pivot 
            (count(id) 
                for drug 
                in ([Drug1], [Drug2], [Drug3], [Drug4], [Drug5]) 
            ) as PivotTable

我知道我可以使用UNION来执行此操作并使用单独的查询来计算总计，但这会使数据库的命中率翻倍。

我找到了使用ROLLUP和CUBE的示例，但这些是不推荐使用的功能，因此我不想使用它们。

还有其他想法，GROUPING SETS吗？

Answer 1

您可以使用GROUPING SETS获取总计行：

select isnull(diagnosis, 'Total') Diagnosis, 
  sum([Drug1]) Drug1, sum([Drug2]) Drug2, 
  sum([Drug3]) Drug3, sum([Drug4]) Drug4, 
  sum([Drug5]) Drug5,
  sum([Drug1] + [Drug2] + [Drug3] + [Drug4] + [Drug5]) as [Total]
from 
(
  Select [id], [drug], [Diagnosis]
  from DrugDiagnosis
) as ptp
pivot 
(
  count(id) 
  for drug in ([Drug1], [Drug2], [Drug3], [Drug4], [Drug5]) 
) as PivotTable
group by grouping sets((diagnosis), ());

请参阅SQL Fiddle with Demo

如何在没有UNION，ROLLUP或CUBE的情况下使用PIVOT表计算总行数？

1 个答案: