Question

import pygame
from pygame.locals import *
import random
import time
pygame.init()


randomNumber = random.randint(1,600)
randomNumber2 = random.randint(1,600)
x = 0
text = ""
squareCount = 0
beenHere = 0
# colours = (red, green, blue)
BLACK = (0, 0, 0)
RED = (255, 0, 0)
GREEN = (0, 255, 0)
WHITE = (255, 255, 255)
LBLUE = (0, 123, 255)

colour = RED

# Make a window appear
size = (700, 500)
screen = pygame.display.set_mode(size)
pygame.display.set_caption("Square Chase | Score: 0")
screen.fill(LBLUE)
pygame.display.flip()

pygame.time.set_timer(USEREVENT + 1, 1500)

done = False
clock = pygame.time.Clock()
while done == False:
for event in pygame.event.get():
    print(event)
    if event.type == pygame.QUIT:
        done = True
    if event.type == USEREVENT + 1:
        screen.fill(LBLUE)
        randomNumber = random.randint(1,625)
        randomNumber2 = random.randint(1,420)
        mySquare = pygame.draw.rect(screen,colour,(randomNumber,randomNumber2,50,50),5)
        squareCount = squareCount + 1
        if squareCount == 50:
            done == true
        pygame.display.flip()
    if event.type == pygame.MOUSEBUTTONDOWN:
        y, z = pygame.mouse.get_pos()
        is_inside = mySquare.collidepoint(y, z)
        if is_inside and colour == GREEN:
            x = x+1
            text = str(x)
            pygame.display.set_caption("Square Chase | Score " + text)
            colour = RED
        elif is_inside:
            x = x+1
            text = str(x)
            pygame.display.set_caption("Square Chase | Score " + text)
            colour = GREEN
clock.tick(20)
pygame.quit()

我的目标是创建一个游戏，用户必须点击正方形才能增加分数。他们有50次机会这样做。如果他们在1.5秒内点击正方形，则方块的颜色会发生变化。

以上代码的工作区别于每次绘制一个新的方块，用户可以点击它说5次，他们的分数会上升5个。有关如何让分数增加一个的任何建议吗？提前谢谢。

Answer 1

希望我可以使用评论，但我缺乏声誉。

我没有浏览你的所有代码，但是你的描述听起来像一个简单的旗帜就能帮助你。

一旦您识别出已单击，则增加分数并设置布尔值。

所以从本质上讲，你会想要一些符合

的内容

if clicked == false
     score = score+1
     clicked = true

一旦出现另一个块，您将希望将该标志清除为假。

Answer 2

如果在成功按键后出现一个新的广场会不会更好？这样游戏就会更有活力。

很容易改变这一点。不是每隔1.5秒使用一次调用的用户事件，而是将clock.tick（）返回的值相加，当它们的总和大于1500毫秒时，创建一个新的矩形。这是一种更好的方法，因为您可以调用创建新方块的方法并在成功按键后立即重置计时器。

一些代码可以帮助您入门：

def new_rect(screen,colour):
    screen.fill(LBLUE)
    randomNumber = random.randint(1,625)
    randomNumber2 = random.randint(1,420)
    mySquare = pygame.draw.rect(screen,colour,(randomNumber,randomNumber2,50,50),5)
    return mySquare

done = False
clock = pygame.time.Clock()
timer_var = 0

while done == False:
    if(timer_var > 1500):
        timer_var = 0
        mySquare = new_rect(screen,color)
        squareCount = squareCount + 1
        if squareCount == 50:
            done == true

    for event in pygame.event.get():
        if event.type == pygame.MOUSEBUTTONDOWN:
            y, z = pygame.mouse.get_pos()
            is_inside = mySquare.collidepoint(y, z)
            if is_inside: 
                x = x+1
                text = str(x)
                pygame.display.set_caption("Square Chase | Score " + text)

                timer_var = 0
                new_rect(screen,colour)
                squareCount = squareCount + 1
                if squareCount == 50:
                    done == true
                if colour == GREEN:
                    colour = RED
                else:
                    colour = GREEN
    timer_var += clock.tick(20)
pygame.quit()

Python点击游戏，更新分数

2 个答案: