我需要从多个表中SELECT来获取如下结果表：
+--------+-------+-------------------+----------------------+
| itemID | level | studyPhraseString | meaningPhraseStrings |
+--------+-------+-------------------+----------------------+
| 1 | 4 | la maison | house |
+--------+-------+-------------------+----------------------+
| 2 | 3 | voler | to fly,to steal |
+--------+-------+-------------------+----------------------+
注意：studyPhraseString和meaningPhraseStrings应该是由word表格中的值组成的串联字符串。
我的表格：
项目
CREATE TABLE `item` (
`itemID` bigint(11) unsigned NOT NULL AUTO_INCREMENT,
`groupID` bigint(11) unsigned NOT NULL,
`studyLang` varchar(5) NOT NULL,
`meaningLang` varchar(5) NOT NULL,
`studyPhraseID` bigint(11) unsigned NOT NULL,
PRIMARY KEY (`itemID`)
) ENGINE=InnoDB AUTO_INCREMENT=14 DEFAULT CHARSET=latin1;
含义
CREATE TABLE `meaning` (
`meaningID` bigint(11) unsigned NOT NULL AUTO_INCREMENT,
`itemID` bigint(11) unsigned NOT NULL,
`meaningPhraseID` bigint(11) unsigned NOT NULL,
`meaningIndex` int(11) unsigned NOT NULL,
PRIMARY KEY (`meaningID`)
) ENGINE=InnoDB AUTO_INCREMENT=16 DEFAULT CHARSET=latin1;
短语
CREATE TABLE `phrase` (
`phraseID` bigint(11) unsigned NOT NULL AUTO_INCREMENT,
`phraseLang` varchar(5) NOT NULL DEFAULT '',
PRIMARY KEY (`phraseID`)
) ENGINE=InnoDB AUTO_INCREMENT=29 DEFAULT CHARSET=latin1;
phrase_word
CREATE TABLE `phrase_word` (
`phrase_wordID` bigint(11) unsigned NOT NULL AUTO_INCREMENT,
`phraseID` bigint(11) unsigned NOT NULL,
`wordID` bigint(11) unsigned NOT NULL,
`wordIndex` int(11) unsigned NOT NULL,
PRIMARY KEY (`phrase_wordID`)
) ENGINE=InnoDB AUTO_INCREMENT=29 DEFAULT CHARSET=latin1;
状态
CREATE TABLE `status` (
`statusID` bigint(11) unsigned NOT NULL AUTO_INCREMENT,
`itemID` bigint(11) unsigned NOT NULL,
`level` tinyint(1) unsigned NOT NULL DEFAULT '0',
`nextReviewTime` int(11) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`statusID`)
) ENGINE=InnoDB AUTO_INCREMENT=14 DEFAULT CHARSET=latin1;
字
CREATE TABLE `word` (
`wordID` bigint(11) unsigned NOT NULL AUTO_INCREMENT,
`string` varchar(64) NOT NULL DEFAULT '',
PRIMARY KEY (`wordID`)
) ENGINE=InnoDB AUTO_INCREMENT=9 DEFAULT CHARSET=latin1;
我写了以下SELECT语句：
SELECT item.itemID, status.level,
(SELECT GROUP_CONCAT(word.string ORDER BY phrase_word.wordIndex SEPARATOR ' ')
FROM word INNER JOIN phrase_word ON word.wordID=phrase_word.wordID
INNER JOIN item AS subItem ON phrase_word.phraseID=subItem.studyPhraseID
WHERE subItem.itemID=item.itemID
GROUP BY subItem.itemID
) AS studyPhraseString
FROM item INNER JOIN status ON item.itemID=status.itemID
WHERE item.groupID=5
ORDER BY status.statusID DESC
这有效，但不包括meaningPhraseString。我无法弄清楚如何将单词连接成短语并将短语连成一个字符串分隔，
我尝试过嵌套的GROUP_CONCAT子句但没有成功（子查询返回超过1行）：
如何编写此声明以包含meaningPhraseStrings？提前谢谢。
PS：我希望这是一个单一的查询
我尝试过以下但是失败了。为什么？它有两级相关查询。
SELECT
item.itemID,
status.level,
(
SELECT GROUP_CONCAT(word.string ORDER BY phrase_word.wordIndex SEPARATOR ' ')
FROM word INNER JOIN phrase_word ON word.wordID=phrase_word.wordID
INNER JOIN item AS subItem ON phrase_word.phraseID=subItem.studyPhraseID
WHERE subItem.itemID=item.itemID
GROUP BY subItem.itemID
) AS studyPhraseString,
(
SELECT GROUP_CONCAT(meaningPhraseString SEPARATOR '.')
FROM (
(
SELECT GROUP_CONCAT(word.string ORDER BY phrase_word.wordIndex SEPARATOR ' ') AS meaningPhraseString
FROM word INNER JOIN phrase_word ON word.wordID=phrase_word.wordID
INNER JOIN meaning ON phrase_word.phraseID=meaning.meaningPhraseID
INNER JOIN item AS subItem ON meaning.itemID=subItem.itemID
WHERE subItem.itemID=item.itemID #This fails
GROUP BY meaning.meaningPhraseID
) AS meaningPhraseString
)
) AS meaningPhraseStrings
FROM item INNER JOIN status ON item.itemID=status.itemID
WHERE item.groupID=5
ORDER BY item.itemID DESC
示例数据：
INSERT INTO `status` VALUES (22,22,0,0),(23,23,0,0),(24,25,0,0),(25,24,0,0),(26,26,0,0);
INSERT INTO `item` VALUES (22,5,'fr','en',49),(23,5,'fr','en',48),(24,5,'fr','en',56),(25,5,'fr','en',50),(26,5,'fr','en',57);
INSERT INTO `meaning` VALUES (27,22,51,0),(28,23,52,0),(29,23,54,1),(30,24,59,0),(31,24,61,1),(32,25,53,0),(33,25,55,1),(34,26,58,0),(35,26,60,1);
INSERT INTO `phrase` VALUES (48,'fr'),(49,'fr'),(50,'fr'),(51,'en'),(52,'en'),(53,'en'),(54,'en'),(55,'en'),(56,'fr'),(57,'fr'),(58,'en'),(59,'en'),(60,'en'),(61,'en');
INSERT INTO `word` VALUES (46,'l\'autobus'),(47,'bus'),(48,'pourquoi'),(49,'comment'),(50,'why'),(51,'ça'),(52,'va?'),(53,'voler'),(54,'incroyable'),(55,'how'),(56,'is'),(57,'to'),(58,'are'),(59,'incredible'),(60,'that?'),(61,'you?'),(62,'fly'),(63,'amazing'),(64,'hi'),(65,'steal');
INSERT INTO `phrase_word` VALUES (86,49,46,0),(87,51,47,0),(88,48,48,0),(89,50,49,0),(90,52,50,0),(91,54,50,0),(92,50,51,1),(93,50,52,2),(94,57,53,0),(95,53,55,0),(96,56,54,0),(97,54,56,1),(98,53,58,1),(99,58,57,0),(100,59,59,0),(101,54,60,2),(102,53,61,2),(103,58,62,1),(104,61,63,0),(105,60,57,0),(106,55,64,0),(107,60,65,1);
SELECT i.itemID,
s.level,
sp.studyPhraseString,
GROUP_CONCAT(mp.meaningPhraseString
SEPARATOR ', ') AS meaningPhraseStrings
FROM item AS i
JOIN meaning AS m ON i.itemID = m.itemID
JOIN status AS s ON i.itemID = s.itemID
JOIN (
SELECT subItem.studyPhraseID,
GROUP_CONCAT(word.string
ORDER BY phrase_word.wordIndex
SEPARATOR ' ') AS studyPhraseString
FROM word
JOIN phrase_word
ON word.wordID=phrase_word.wordID
JOIN item AS subItem
ON phrase_word.phraseID=subItem.studyPhraseID
GROUP BY subItem.studyPhraseID
) AS sp ON i.studyPhraseID = sp.studyPhraseID
JOIN (
SELECT meaning.meaningPhraseID,
GROUP_CONCAT(word.string
ORDER BY phrase_word.wordIndex
SEPARATOR ' ') AS meaningPhraseString
FROM word
JOIN phrase_word ON word.wordID=phrase_word.wordID
JOIN meaning ON phrase_word.phraseID=meaning.meaningPhraseID
JOIN item AS subItem ON meaning.itemID=subItem.itemID
GROUP BY meaning.meaningPhraseID
) AS mp ON m.meaningPhraseID = mp.meaningPhraseID
GROUP BY i.itemID, s.level, sp.studyPhraseString
ORDER BY i.itemID, s.level, sp.studyPhraseString
答案 0 :(得分：1)
你的问题似乎是这样的：
如何将单词连接成短语并将短语连成一个字符串
让我们分解吧。您需要将五个表连接在一起。其中三个是物理表，即item，meaning和status。从这些表中，您可以获得所需的结果集项的引用，称为itemID和level，并获得项之间的关系及其含义。
您需要的其他两个表是虚拟表（即子查询）。其中一个为您提供法语短语，另一个为您提供英语翻译。
让我们为虚拟表创建两个查询。我们先把这些单词写成短语。像这样的查询实现了这个目标。
SELECT subItem.studyPhraseID,
GROUP_CONCAT(word.string
ORDER BY phrase_word.wordIndex
SEPARATOR ' ') AS studyPhraseString
FROM word
INNER JOIN phrase_word ON word.wordID=phrase_word.wordID
INNER JOIN item AS subItem ON phrase_word.phraseID=subItem.studyPhraseID
GROUP BY subItem.studyPhraseID
这将为您提供短语ID编号和短语的结果集表。根据您的样本，这是一个SQL小提琴。 http://sqlfiddle.com/#!2/11ae2/9/0
然后，创建一个类似的查询，为您提供meaningPhraseString值。
SELECT meaning.meaningPhraseID,
GROUP_CONCAT(word.string
ORDER BY phrase_word.wordIndex
SEPARATOR ' ') AS meaningPhraseString
FROM word
INNER JOIN phrase_word ON word.wordID=phrase_word.wordID
INNER JOIN meaning ON phrase_word.phraseID=meaning.meaningPhraseID
INNER JOIN item AS subItem ON meaning.itemID=subItem.itemID
GROUP BY meaning.meaningPhraseID
这给出了id和含义短语的列表。这是小提琴。 http://sqlfiddle.com/#!2/11ae2/6/0
因此，我们需要一个五向连接（三个物理表和两个子查询）才能到达我们的最终结果集。总之，它看起来像这样：
SELECT i.itemID,
s.level,
sp.studyPhraseString,
mp.meaningPhraseString
FROM item AS i
JOIN meaning AS m ON i.itemID = m.itemID
JOIN status AS s ON i.itemID = s.itemID
JOIN (
/* the studyPhrase subquery */
) AS sp ON i.studyPhraseID = sp.studyPhraseID
JOIN (
/* the meaningPhrase subquery */
) AS mp ON m.meaningPhraseID = mp.meaningPhraseID
这里的技巧是你可以互换地使用查询（或虚拟表）和物理表。因此，当您需要汇总一堆表时，可以创建一个查询来执行该操作，然后将其粘贴到JOIN (/*query*/) AS alias中。
最后，您需要通过在查询中添加另一个to fly, to steal和GROUP_CONCAT()来创建加入逗号的字符串（例如GROUP BY）。最终结果是
SELECT i.itemID,
s.level,
sp.studyPhraseString,
GROUP_CONCAT(mp.meaningPhraseString
SEPARATOR ', ') AS meaningPhraseStrings
FROM item AS i
JOIN meaning AS m ON i.itemID = m.itemID
JOIN status AS s ON i.itemID = s.itemID
JOIN (
/* the studyPhrase subquery */
) AS sp ON i.studyPhraseID = sp.studyPhraseID
JOIN (
/* the meaningPhrase subquery */
) AS mp ON m.meaningPhraseID = mp.meaningPhraseID
GROUP BY i.itemID, s.level, sp.studyPhraseString
ORDER BY i.itemID, s.level, sp.studyPhraseString
那是你的疑问。 http://sqlfiddle.com/#!2/11ae2/16/0它肯定会利用结构化查询语言中的结构化。