Question

我有这个查询（使用SQL Server 2008）：

SELECT  
    ISNULL(tt.strType,'Random'), 
    COUNT(DISTINCT t.intTestID) as Qt_Tests,    
    COUNT(CASE WHEN sd.intResult=4 THEN 1 ELSE NULL END) as Positives
FROM TB_Test t 
LEFT JOIN TB_Sample s ON t.intTestID=s.intTestID 
LEFT JOIN TB_Sample_Drug sd ON s.intSampleID=sd.intSampleID
LEFT JOIN TB_Employee e ON t.intEmployeeID=e.intEmployeeID
LEFT JOIN TB_Test_Type tt ON t.intTestTypeID=tt.intTestTypeID
WHERE 
    s.dtmCollection BETWEEN '2013-06-01 00:00' AND '2013-08-31 23:59'
    AND f.intCompanyID = 91
GROUP BY    
    tt.strType

事情是每个样本在sample_drug上有四个记录，代表在该样本上测试的药物。并且样品的结果可以同时为一至四种药物呈阳性。我需要在第三栏中展示的是，无论药物多少，样本都是阳性的。我找不到办法做到这一点，因为我需要CASE WHEN知道我想要所有结果= 4但只是来自唯一的intSampleIDs。

提前致谢！

Answer 1

如果我理解正确，最简单的方法是使用max()代替count()：

SELECT ISNULL(tt.strType,'Random'), 
       COUNT(DISTINCT t.intTestID) as Qt_Tests,    
       max(CASE WHEN sd.intResult = 4 THEN 1 ELSE NULL END) as HasPositives
. . .

编辑：

如果您希望结果为阳性的样本数量，请使用count(distinct)语句使用case。

SELECT ISNULL(tt.strType,'Random'), 
       COUNT(DISTINCT t.intTestID) as Qt_Tests,    
       count(distinct CASE WHEN sd.intResult = 4 THEN s.intSampleID end) as NumPositiveSamples

Answer 2

而不是：

COUNT(CASE WHEN sd.intResult=4 THEN 1 ELSE NULL END) as Positives

试试这个：

SUM(CASE WHEN sd.intResult=4 THEN 1 ELSE 0 END) as Positives

Answer 3

如果我理解你想要显示在阳性列中标记为intResult = 4（1）或不是（null）的TB Sample Drug中的行，那么应该有效。

    SELECT  
        ISNULL(tt.strType,'Random'), 
        COUNT(DISTINCT t.intTestID) as Qt_Tests,    
        CASE WHEN sd.Positives > 0 THEN 1 ELSE NULL END as Positives
    FROM TB_Test t 
    LEFT JOIN TB_Sample s ON t.intTestID=s.intTestID 
    LEFT JOIN TB_Employee e ON t.intEmployeeID=e.intEmployeeID
    LEFT JOIN TB_Test_Type tt ON t.intTestTypeID=tt.intTestTypeID
    CROSS APPLY (select count(*) as Positives from TB_Sample_Drug sd where s.intSampleID=sd.intSampleID and sd.intResult=4) sd 
    WHERE 
        s.dtmCollection BETWEEN '2013-06-01 00:00' AND '2013-08-31 23:59'
        AND f.intCompanyID = 91
    GROUP BY    
        tt.strType

使用Case计算唯一ID

3 个答案: