我想开始一项新活动,该活动会播放来自源的直播。当我开始活动时,它会在整个屏幕上播放内容。我想在一个小视图中显示流的内容,这是一个surfaceview。我通过使用运行runnable等的处理程序来完成此操作。我就是这样做的:
//new activity played from here
Intent localIntent3 = new Intent("android.intent.action.MAIN");
//intent flag set to start a new task over the previous one
localIntent3.setFlags(270532608);
startActivity(localIntent3);
启动此活动后,我在相应的处理程序上运行runnable,该处理程序在表面视图上呈现流上播放的内容。我是这样做的:
Runnable handlerRuntv = new Runnable() {
public void run() {
try {
MainActivity.this.surfaceView = new SurfaceView(
MainActivity.this.getApplicationContext());
MainActivity.this.openSurfaceView();
//method to scale the surface view to a smaller display
MainActivity.this.setPipscale();
} catch (Exception localException) {
localException.printStackTrace();
}
}
};
这是我在处理程序上运行它的方式:
this.handlerTV.postDelayed(handlerRuntv, 300L);
一旦runnable开始在处理程序上运行,我在设备上执行back press
,将我带到上一个已播放内容的活动。
Question
:我想直接在曲面的缩放显示上启动活动,即我不希望用户按后退按钮查看流。该怎么做?
**EDIT:**
使用片段启动片段中的活动:
//In mainactivity.java
llFragment =(LinearLayout) findViewById(R.id.llfragment);
FragmentTransaction t = getFragmentManager().beginTransaction();
RunTVFragment fragment = new RunFragment();
t.add(llFragment.getId(), fragment, "fragment");
t.commit();
//llfragment in .xml
<LinearLayout
android:id="@+id/llfragment"
android:orientation="horizontal"
android:layout_width="wrap_content"
android:layout_height="wrap_content" >
</LinearLayout>
启动活动的 RunFragment.java
:
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
// TODO Auto-generated method stub
View v = inflater.inflate(R.layout.fragmentlayout, container, false);
return v;
}
@Override
public void onActivityCreated(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onActivityCreated(savedInstanceState);
Intent localIntent3 = new Intent("android.intent.action.MAIN");
localIntent3.addCategory("android.intent.category.LAUNCHER");
startActivity(localIntent3);
this.handlerTV.postDelayed(handlerRuntv, 300L);
}
//fragmentlayout.xml
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@drawable/back"
android:orientation="horizontal" >
<FrameLayout
android:id="@+id/surframelayout"
android:layout_width="340dp"
android:layout_height="280dp"
android:layout_alignParentRight="true"
android:layout_below="@+id/textView1"/>
</RelativeLayout>
但是,活动不会在所需的屏幕区域中开始/显示。相反,它作为一项新任务开始,超过之前的活动..
EDIT II:
NONUIFragment的定义:
@Override
public void onActivityCreated(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onActivityCreated(savedInstanceState);
ComponentName localComponentName2 = new ComponentName("mstar.tvsetting.ui", "mstar.tvsetting.ui.RootActivity");
Intent localIntent3 = new Intent("android.intent.action.MAIN");
localIntent3.addCategory("android.intent.category.LAUNCHER");
localIntent3.setComponent(localComponentName2);
localIntent3.setFlags(270532608);
startActivity(localIntent3);
this.handlerTV.postDelayed(handlerRuntv, 1000L);
}
从NONUI-Fragment
:
UI-Fragment
@Override
public void onActivityCreated(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onActivityCreated(savedInstanceState);
FragmentManager fm = getFragmentManager();
// Check to see if we have retained the worker fragment.
NonUITVFragment mWorkFragment = (NonUITVFragment)fm.findFragmentByTag("work");
// If not retained (or first time running), we need to create it.
if (mWorkFragment == null) {
mWorkFragment = new NonUITVFragment(); //create instance of NON UI Fragment
// Tell it who it is working with.
mWorkFragment.setTargetFragment(this, 0);
fm.beginTransaction().add(mWorkFragment, "work").commit(); //NON UI Fragment
}
}
从我的主要活动中调用UI-Fragment
:
if (savedInstanceState == null) { //UI Fragement
getFragmentManager().beginTransaction().add(R.id.llfragment, new RunTVFragment()).commit();
}
答案 0 :(得分:0)
我怀疑我是否理解你的问题。也许你可以尝试使用没有UI的片段来启动线程而不是活动。