Question

void Test(Packets& packet)
{
      char buf[BUFLEN];
      char* offset = buf;
      unsigned int foo;
      for(;!gzeof(file_handle);){
            int len = gzread(file_handle, offset, sizeof(buf)-(offset-buf));
            char* cur = buf;
            char* end = offset+len;
            for (char* eol; (cur<end) && (eol = std::find(cur, end, '\n')) < end; cur = eol + 1)
            {
                string string_array = string(cur, eol);
                if(string_array[0] == 'L'){
                    packet.foo = blah;
                }else{
                    packet.foo = bar;
                }
                //After readnig a line.. how do I make sure it quits this function (does another job in some other function) and continous from the next line?
            }
#ifdef ROTATION
        offset = std::rotate(buf, cur, end);
#else
        offset = buf + (end-cur);
        std::rotate(buf, cur, end);
#endif
    }
    std::cout<<std::string(buf, offset) ;
}

读取一行之后..如何确保它退出此功能（在其他功能中执行另一项工作）并从下一行继续？我尝试将buf作为全局变量进行偏移，并仅在缓冲区为空时读取文件..它仍然不起作用。

Answer 1

为什么要退出该功能并从下一行继续？

改变你的功能，就像读一行一样，另一行做任何事情

在某个地方，你可能想做一些像我这样的错误？

{
Packets myPacket;
Test(packet);
OtherFunction(packet);
}

使用c ++查找文件

1 个答案: