Question

我有一个AppWidget这个应用程序，当用户点击它时，它会发送一个短信。通过单击小部件发送SMS工作正常。现在，我想知道SMS的发送是成功还是失败。我该怎么做？

以下是发送短信的代码

String sms2 = id + " " + name + " " + cn.getName() + " " + message
                                    + " " + lati + " " + longi 
                                    + " https://maps.google.com/?q=" + lati + "," + longi + " -alertoapp";
                            String cp = cn.getPhoneNumber();
                            PendingIntent piSent=PendingIntent.getBroadcast(context, 0, new Intent("SMS_SENT"), 0);
                            PendingIntent piDelivered=PendingIntent.getBroadcast(context, 0, new Intent("SMS_DELIVERED"), 0);
                            SmsManager sms = SmsManager.getDefault();
                            sms.sendTextMessage(cp, null, sms2, piSent, piDelivered);

清单

<receiver android:name=".Widget" android:label="@string/app_name">
        <intent-filter>
            <action android:name="android.appwidget.action.APPWIDGET_UPDATE" />
            <!-- Broadcast Receiver that will also process our self created action -->
            <action android:name="de.thesmile.android.widget.buttons.ButtonWidget.ACTION_WIDGET_RECEIVER"/>
        </intent-filter>
        <meta-data android:name="android.appwidget.provider" android:resource="@xml/widget_provider" />
    </receiver>

我想使用下面的方法来解决是否发送SMS的问题，但问题是在BroadCastReceiver类中没有registerReceiver方法。

 switch (getResultCode()) {
            case Activity.RESULT_OK:
                clear1();
                clear2();
                clear3();
                clear4();
                Toast.makeText(getBaseContext(), "SMS has been sent", Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                Toast.makeText(getBaseContext(), "Generic Failure", Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_NO_SERVICE:
                Toast.makeText(getBaseContext(), "No Service", Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_NULL_PDU:
                Toast.makeText(getBaseContext(), "Null PDU", Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_RADIO_OFF:
                Toast.makeText(getBaseContext(), "Radio Off", Toast.LENGTH_SHORT).show();
                break;
            default:
                Toast.makeText(getApplicationContext(), "Coordinates is null, Try again", Toast.LENGTH_LONG).show();
                break;
            }

        }
    };
    smsDeliveredReceiver=new BroadcastReceiver() {

        @Override
        public void onReceive(Context arg0, Intent arg1) {
            // TODO Auto-generated method stub
            switch(getResultCode()) {
            case Activity.RESULT_OK:
                Toast.makeText(getBaseContext(), "SMS Delivered", Toast.LENGTH_SHORT).show();
                break;
            case Activity.RESULT_CANCELED:
                Toast.makeText(getBaseContext(), "SMS not delivered", Toast.LENGTH_SHORT).show();
                break;
            }
        }
    };
    registerReceiver(smsSentReceiver, new IntentFilter("SMS_SENT"));
    registerReceiver(smsDeliveredReceiver, new IntentFilter("SMS_DELIVERED"));

有什么建议吗？

Answer 1

对于那些遇到同样问题的人，我已经在this

的帮助下解决了这个问题。

所以这是

smsSentReceiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context ctx, Intent arg1) {
        String msg = "";
        switch (getResultCode()) {
            case Activity.RESULT_OK:
                msg = "SMS has been sent";
                break;
            case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                msg = "Generic Failure";
                break;
            case SmsManager.RESULT_ERROR_NO_SERVICE:
                msg = "No Service";
                break;
            case SmsManager.RESULT_ERROR_NULL_PDU:
                msg = "Null PDU";
                break;
            case SmsManager.RESULT_ERROR_RADIO_OFF:
                msg = "Radio Off";
                break;
            default:
                msg = "Coordinates is null, Try again";
                break;
        }
        Toast.makeText(ctx.getApplicationContext(), msg, Toast.LENGTH_LONG).show();
    }
};

smsDeliveredReceiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context ctx, Intent arg1) {
        String msg = "";
        switch (getResultCode()) {
            case Activity.RESULT_OK:
                msg = "SMS Delivered";
                break;
            case Activity.RESULT_CANCELED:
                msg = "SMS not delivered";
                break;
        }
        Toast.makeText(ctx.getApplicationContext(), msg, Toast.LENGTH_LONG).show();
    }
};

ctx.getApplicationContext()
    .registerReceiver(smsSentReceiver, new IntentFilter("SMS_SENT"));
ctx.getApplicationContext()
    .registerReceiver(smsDeliveredReceiver, new IntentFilter("SMS_DELIVERED"));

结论：因此，要在BroadcastReceiver类中注册接收器。

而不是registerReceiver(smsSentReceiver, new IntentFilter("SMS_SENT"));

使用context.getApplicationContext().registerReceiver(smsSentReceiver, new IntentFilter("SMS_SENT"));

如何在BroadcastReceiver AppWidgetProvider类中注册broadcastreceiver？

1 个答案: