如何使用createQueryBuilder在Doctrine2中嵌套两个AND查询?

时间:2014-01-30 06:56:43

标签: sql doctrine-orm createquery

以下是我的查询:

$em = \Zend_Registry::get('em');
    $qb_1 = $em->createQueryBuilder();
    $q_1 = $qb_1->select('link_req')
    ->from('\Entities\link_requests','link_req')
    ->where( 'link_req.is_confirmed = 1' )
    ->andWhere('link_req.$link_requestsSenderUser='.$user1_id .'or'.' link_req.$link_requestsSenderUser='.$user2_id)
    ->andWhere('link_req.$link_requestsReceiverUser='.$user1_id .'or'.' link_req.$link_requestsReceiverUser='.$user2_id);
    $result= $q_1->getDql();
    echo $result;

我想要以下查询:

SELECT * FROM [fb_local].[dbo].[link_requests]  
WHERE is_confirmed = 1 AND (request_user_id = 12  or request_user_id=19) AND (accept_user_id = 12 or  accept_user_id = 19)

1 个答案:

答案 0 :(得分:0)

您的SQL只是一个查询,所以不确定您要嵌套的是什么。但请尝试以下方法:

$em = \Zend_Registry::get('em');
    $qb_1 = $em->createQueryBuilder();
    $q_1 = $qb_1->select('link_req')
        ->from('\Entities\link_requests','link_req')
        ->where( 'link_req.is_confirmed = 1' )
        ->andWhere('link_req.link_requestsSenderUser=:user_id or link_req.link_requestsSenderUser=:user_id')
        ->andWhere('link_req.link_requestsReceiverUser=:user_id or link_req.link_requestsReceiverUser=:user_id');
    $q_1->setParameter('user_id', $user1_id);
    $query = $q_1->getQuery();
    echo $query->getSql();

请注意我如何移除$前面的link_requestsReceiverUser。我还从$user1_id创建了一个参数,这会阻止SQL injections

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