Question

首先，我想首先说我不仅仅是在寻找某人给我这个问题的答案，我是一名初学程序员，我只是想尽可能多地学习。对我的代码的批评和对正确方向的友好推动将是非常感谢！让我感到困惑的是我的stringParser方法。我使用这种方法循环遍历字符串，挑选数字并将它们存储在要解析的新字符串中。令我困惑的是我如何将这些数字加在一起？这是代码：

public static int stringParser(String parsee,int parsed)
{
    int indexOfString = parsee.indexOf("=");            //Searches for an = sign since there has to be one  
    String parsee2 = "";
    int [] newArray;
    String subStringParse = parsee.substring(0,indexOfString);      //Substring made to divide string, this one is from 0 index to 1st occurence of = 
    for(int i = 0;i<subStringParse.length();i++)
    {
        if(Character.isDigit(subStringParse.charAt(i)))     //if the value is a number it is stored in a new string then parsed.
        {
            parsee2+= subStringParse.charAt(i);
            parsed = Integer.parseInt(parsee2);

        }           
    }           return parsed;

}
public static int sumInts(int a,int storedSums)
{   
    //a = new int[20];
    for(int i=0;i<a;i++)    //loops through parsed string from stringParser
    {
        storedSums += a;            //creates a new value calculating sum 
    }   
    return storedSums;
}

Answer 1

根据我的猜测，你想解析像这样的东西`12 + 34 ='。

如果我是对的，那么你的for循环是完全错误的。它将仅返回34作为整数值。您可以为此调试代码。

我建议你这样：

int index = 0;
for(int i = 0;i<subStringParse.length();i++)
{
    if(Character.isDigit(subStringParse.charAt(i)))     //if the value is a number it is stored in a new string then parsed.
    {
        parsee2+= subStringParse.charAt(i);
        parsed = Integer.parseInt(parsee2);
    }           
    newArray[index++] = parsed; //make sure you initialize newArray.
}      
return newArray;

Answer 2

尝试，

String parsee = "12+13 = 34+45 = 45+-45";
int value = 0;
String parsed = "";
for(String exp : parsee.split("=")){            
    for(String val : exp.trim().split("\\+")){
        value+=Integer.parseInt(val);
    }
    parsed+=" SUM = "+value;
    value = 0;
}
System.out.println(parsed);

输出

 SUM = 25 SUM = 79 SUM = 0

Java：将字符串解析为int并计算总和

2 个答案: