Question

我想在android中解析这个json数组？在android中执行它的最佳方法是什么？创建json数组到相关android json解析的最佳方法是什么。

MySql表数据（样本）

key | name | lgtime
--------------------
1   | Cat 1| 899011
2   | Cat 2| 899011
3   | Cat 3| 899011
4   | Cat 4| 899011

这个json数组是从php

创建的

public static function getCategory($_lgtime) {
        $con = JsonDataManip::connect();
        $stmt = $con->prepare("select * from " . _TABLE_CATEGORY . " where lgtime > ?");
        $stmt->execute(array($_lgtime));
        while ($row = $stmt->fetch()) {
            $jsonArray['key'] = $row['key'];
            $jsonArray['name'] = $row['name'];
            $jsonArray['lgtime'] = $row['lgtime'];
            $json[] = $jsonArray;
        }
        return $json;
    }

用法：（php）

echo json_encode(JsonDataManip::getCategory('899011'));

[{
"key":"1",
"name":"Cat 1",
"lgtime":"899011"
},
{
"key":"2",
"name":"Cat2",
"lgtime":"899011"
},
{
"key":"3",
"name":"Cat 3",
"lgtime":"899011"
}

Answer 1

// try this way and let me know still have problem
public class MyActivity extends Activity {


    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        try{
            JSONArray jsonArray = new JSONArray("jsonArrayString");

            ArrayList<HashMap<String,String>> list = (ArrayList<HashMap<String,String>>)toList(jsonArray);

        }catch (Exception e){
            e.printStackTrace();
        }


    }

    private Object fromJson(Object json) throws JSONException {
        if (json == JSONObject.NULL) {
            return null;
        } else if (json instanceof JSONObject) {
            return jsonToMap((JSONObject) json);
        } else if (json instanceof JSONArray) {
            return toList((JSONArray) json);
        } else {
            return json;
        }
    }

    public Map<String, String> jsonToMap(JSONObject object) throws JSONException {
        Map<String, String> map = new HashMap();
        Iterator keys = object.keys();
        while (keys.hasNext()) {
            String key = (String) keys.next();
            map.put(key, fromJson(object.get(key)).toString());
        }
        return map;
    }

    @SuppressWarnings({ "rawtypes", "unchecked" })
    private List toList(JSONArray array) throws JSONException {
        List list = new ArrayList();
        int size = array.length();
        for (int i = 0; i < size; i++) {
            list.add(fromJson(array.get(i)));
        }
        return list;
    }


}

Answer 2

试试这种方式

try {
            JSONArray arrJsonArray = new JSONArray("AboveJsonString");
            for (int i = 0; i < arrJsonArray.length(); i++) {
                JSONObject object = arrJsonArray.getJSONObject(i);
                System.out.println("Key :" + object.getString("key"));
                System.out.println("name :" + object.getString("name"));
                System.out.println("lgtime :" + object.getString("lgtime"));
            }
        } catch (Exception e) {
        }

Answer 3

将此字符串放在String对象

中

喜欢

String jsonString = "[
 {
   'key': '1',
   'name': 'Category 10',
   'lgtime': '20140129184514896'
 },
 {
   'key': '2',
   'name': 'Category 9',
   'lgtime': '20140129184514896'
 },
 {
   'key': '3',
   'name': 'Category 8',
   'lgtime': '20140129184514896'
 }
]"

创建JSONArray类的对象

赞：JSONArray jsonArr = new JSONArray(jsonString)

现在创建一个循环

for (int i = 0; i < jsonArr .length(); i++) {           
JSONObject obj = jsonArr.getJSONObjetc(i);                        
// Access you element bu this object like obj.getString("key");
}

如何在android中解析没有root元素的json数组？

3 个答案: