Question

这应该是一个骰子应用程序，每个骰子应该在3种颜色之间交替，所以每个面值可以是蓝色，黄色或红色，到目前为止我只是使第一个骰子着色。现在我有一个数组存储用于每种颜色的所有图像，数组中有18个值，因为骰子有6个边，每边有3个颜色。所以我的方法在数组中取0-2，红色蓝色和黄色都应该是1，然后2-5应该是红蓝黄色的2。问题是每当我运行它时，它显示的总数永远不是正确的toal，因为面值总是关闭。例如，它将显示红色3和正常的黑色和白色1，总数将为8.任何帮助将不胜感激！

public class MainActivity extends Activity {

int[] images = new int[] {

        // dicex1
        R.drawable.dicex1red,
        R.drawable.dicex1blue,
        R.drawable.dicex1yellow,

        // dicex2
        R.drawable.dicex2red,
        R.drawable.dicex2blue,
        R.drawable.dicex2yellow,

        // dicex3
        R.drawable.dicex3red,
        R.drawable.dicex3blue,
        R.drawable.dicex3yellow,

        // dicex4
        R.drawable.dicex4red,
        R.drawable.dicex4blue,
        R.drawable.dicex4yellow,

        // dicex5
        R.drawable.dicex5red,
        R.drawable.dicex5blue,
        R.drawable.dicex5yellow,

        // dicex6
        R.drawable.dicex6red, 
        R.drawable.dicex6blue,
        R.drawable.dicex6yellow, };

Random three = new Random();

MediaPlayer mp;
ImageView dice1, dice2;
TextView total;
Button roll;
int di1, di2, num;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    roll = (Button) findViewById(R.id.bRoll);
    total = (TextView) findViewById(R.id.tvTotal);
    dice1 = (ImageView) findViewById(R.id.IVdice1);
    dice2 = (ImageView) findViewById(R.id.IVdice2);
    mp = new MediaPlayer();
    final Random random = new Random();

    roll.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            mp.release();
            di1 = random.nextInt(6);
            di1++;
            di2 = random.nextInt(6);
            di2++;

            if (di1 == 1) {
                numb(2);

                numColor();
            } else if (di1 == 2) {
                numb(5); 
                num = num + 3;
                numColor();
            } else if (di1 == 3) {
                numb(8); 
                num = num + 6;
                numColor();
            } else if (di1 == 4) {
                numb(11); 
                num = num + 9;
                numColor();
            } else if (di1 == 5) {
                numb(14); 
                num = num + 12;
                numColor();
            } else if (di1 == 6) {
                numb(17); 
                num = num + 15 ;
                numColor();
            }

            if (di2 == 1) {
                dice2.setImageResource(R.drawable.dicex1);
            } else if (di2 == 2) {
                dice2.setImageResource(R.drawable.dicex2);
            } else if (di2 == 3) {
                dice2.setImageResource(R.drawable.dicex3);
            } else if (di2 == 4) {
                dice2.setImageResource(R.drawable.dicex4);
            } else if (di2 == 5) {
                dice2.setImageResource(R.drawable.dicex5);
            } else if (di2 == 6) {
                dice2.setImageResource(R.drawable.dicex6);
            }
            int answer = di1 + di2;
            total.setText("The total is " + answer);

            mp = MediaPlayer.create(getApplicationContext(),
R.raw.dice);
            mp.start();

        }

    });

}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.main, menu);
    return true;
}

public void numColor() {



    if (num == 1) {
        dice1.setImageResource(images[0]);
    } else if (num == 2) {
        dice1.setImageResource(images[1]);
    } else if (num == 3) {
        dice1.setImageResource(images[2]);
    } else if (num == 4) {
        dice1.setImageResource(images[3]);
    } else if (num == 6) {
        dice1.setImageResource(images[4]);
    } else if (num == 7) {
        dice1.setImageResource(images[5]);
    } else if (num == 8) {
        dice1.setImageResource(images[6]);
    } else if (num == 9) {
        dice1.setImageResource(images[7]);
    } else if (num == 10) {
        dice1.setImageResource(images[8]);
    } else if (num == 11) {
        dice1.setImageResource(images[11]);
    } else if (num == 12) {
        dice1.setImageResource(images[12]);
    } else if (num == 13) {
        dice1.setImageResource(images[13]);
    } else if (num == 14) {
        dice1.setImageResource(images[14]);
    } else if (num == 15) {
        dice1.setImageResource(images[15]);
    } else if (num == 16) {
        dice1.setImageResource(images[16]);
    } else if (num == 17) {
        dice1.setImageResource(images[17]);
    } else if (num == 18) {
        dice1.setImageResource(images[18]);
    } 
}

public void numb(int x){
    num = three.nextInt(x);
}
}

Answer 1

这就是我要做的事情

private static final int RED = 0;
private static final int BLUE = 1;
private static final int YELLOW = 2;

private int getResourceForDie(int color, int value) {
    return images[3*(value - 1) + color];
}

因此，为了获得值为3的黄色骰子的资源，您可以调用getResourceForDie(YELLOW, 3)，其中值介于1和6之间。

方法不是从数组中提取正确的变量

1 个答案: