Question

此Oracle查询有什么问题。我正在尝试嵌套的case表达式，但无法找到查询失败的原因。

SELECT USER_ID,
ADVISER_FORENAME,
ADVISER_SURNAME,
AGENT_CODE,
'ABC@WIPRO.COM' AS EMAIL_ADDRESS,
SUBMISSION_DATE,
STATUS_CHANGED_DATE,
CASE
  WHEN (
    CASE
      WHEN TO_CHAR(TRUNC(status_changed_date), 'DY')                          IN ('fri','sat','sun')
      THEN ((TRUNC(STATUS_CHANGED_DATE)               - (TRUNC(SUBMISSION_DATE)))>4)
      ELSE ((TRUNC(STATUS_CHANGED_DATE)               - (TRUNC(SUBMISSION_DATE)))>6)
    END)
  THEN 'B'
  ELSE 'A'
END AS CATEGORY_CODE,
PLAN_REF,
PRODUCT_CODE,
CASE
  WHEN ((TRUNC(STATUS_CHANGED_DATE) - TRUNC(SUBMISSION_DATE))>4)
  THEN 'IPP'
  ELSE 'ICP'
  END AS TOUCHPOINT_NAME
 FROM PIPELINE_PLAN
 WHERE STATUS                                              =26
 AND PRODUCT_TYPE                                          =1  
 AND (TRUNC(STATUS_CHANGED_DATE) - TRUNC(SUBMISSION_DATE))<=4;

当我尝试跑步时，会出现以下错误：

ORA-00907：缺少右括号 00907. 00000 - “缺少右括号” *原因：
*行动：行错误：53列：84

我检查了缺失的括号，但没有找到。

请帮忙。

Answer 1

你的嵌套CASE有点太聪明了。在oracle中，比较（产生3向布尔结果TRUE/FALSE/UNKNOWN）和表达式（产生其他类型的值）是不可互换的。

CASE表达式的结果不是布尔值，因此它不能用作外WHEN中CASE的参数，这需要布尔值。< / p>

您的查询中有这样的结构：

CASE
  WHEN (
    CASE
      WHEN x IN ('1','2','3')
      THEN (y>4)
      ELSE (y>6)
    END)
  THEN 'B'
  ELSE 'A'
END

需要重写为

CASE
  WHEN y > (CASE WHEN x IN ('1','2','3') THEN 4 ELSE 6 END)
  THEN 'B'
  ELSE 'A'
END

或

CASE
  WHEN (x IN ('1','2','3') AND y>4) OR (x NOT IN ('1','2','3') AND y>6)
  THEN 'B'
  ELSE 'A'
END

Answer 2

我没有看到括号有问题，但您不能在then的{{1}}子句中使用布尔值作为结果。也许这个版本可行：

case

此外，根据SELECT USER_ID, ADVISER_FORENAME, ADVISER_SURNAME, AGENT_CODE, 'ABC@WIPRO.COM' AS EMAIL_ADDRESS, SUBMISSION_DATE, STATUS_CHANGED_DATE, (CASE WHEN (TRUNC(STATUS_CHANGED_DATE) - TRUNC(SUBMISSION_DATE) > 4 and TO_CHAR(TRUNC(status_changed_date), 'DY') IN ('fri','sat','sun') ) or (TRUNC(STATUS_CHANGED_DATE) - TRUNC(SUBMISSION_DATE) > 6 and TO_CHAR(TRUNC(status_changed_date), 'DY') not IN ('fri','sat','sun') ) THEN 'B' ELSE 'A' END) AS CATEGORY_CODE, PLAN_REF, PRODUCT_CODE, (CASE WHEN TRUNC(STATUS_CHANGED_DATE) - TRUNC(SUBMISSION_DATE) > 4 THEN 'IPP' ELSE 'ICP' END) AS TOUCHPOINT_NAME FROM PIPELINE_PLAN WHERE STATUS = 26 AND PRODUCT_TYPE = 1 AND TRUNC(STATUS_CHANGED_DATE) - TRUNC(SUBMISSION_DATE) <= 4;子句，条件where永远不会成立。

嵌套的case表达式在sql查询中给出错误

2 个答案: