简单的PHP计算器

时间：2014-01-29 23:54:07

标签： php calculator

我正在创建一个基本的PHP计算器，您可以输入两个值并选择运算符然后显示答案。一切都运行正常，除了它没有输出浏览器的答案。

以下是我的html和PHP文件的代码：            

<head>
<meta charset="utf-8">
<title>Calculator</title>
</head>
<body>
<form method="post" attribute="post" action="disp_form.php">
<p>First Value:<br/>
<input type="text" id="first" name="first"></p>
<p>Second Value:<br/>
<input type="text" id="second" name="second"></p>
<input type="radio" name="group1" id="add" value="add" checked="true"><p>+</p><br/>
<input type="radio" name="group1" id="subtract" value="subtract"><p>-</p><br/>
<input type="radio" name="group1" id="times" value="times"><p>x</p><br/>
<input type="radio" name="group1" id="divide" value="divide"><p>/</p><br/>
<p></p>
<button type="submit" name="answer" id="answer" value="answer">Calculate</button>
</form>
</body>
</html>

PHP文件：

<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Answer</title>
</head>
<body>
<p>The answer is: 
<?php
if($_POST['group1'] == add) {
echo "$first + $second";
}
else if($_POST['group1'] == subtract) {
echo "$first - $second";
}
else if($_POST['group1'] == times) {
echo "$first * $second";
}
else($_POST['group1'] == divide) {
echo "$first / $second";
}
?>
</p> 
</body>
</html>

11 个答案:

答案 0 :(得分：9)

<?php 
$result = "";
class calculator
{
    var $a;
    var $b;

    function checkopration($oprator)
    {
        switch($oprator)
        {
            case '+':
            return $this->a + $this->b;
            break;

            case '-':
            return $this->a - $this->b;
            break;

            case '*':
            return $this->a * $this->b;
            break;

            case '/':
            return $this->a / $this->b;
            break;

            default:
            return "Sorry No command found";
        }   
    }
    function getresult($a, $b, $c)
    {
        $this->a = $a;
        $this->b = $b;
        return $this->checkopration($c);
    }
}

$cal = new calculator();
if(isset($_POST['submit']))
{   
    $result = $cal->getresult($_POST['n1'],$_POST['n2'],$_POST['op']);
}
?>

<form method="post">
<table align="center">
    <tr>
        <td><strong><?php echo $result; ?><strong></td>
    </tr>
    <tr>
        <td>Enter 1st Number</td>
        <td><input type="text" name="n1"></td>
    </tr>

    <tr>
        <td>Enter 2nd Number</td>
        <td><input type="text" name="n2"></td>
    </tr>

    <tr>
        <td>Select Oprator</td>
        <td><select name="op">
            <option value="+">+</option>
            <option value="-">-</option>
            <option value="*">*</option>
            <option value="/">/</option>
        </select></td>
    </tr>

    <tr>
        <td></td>
        <td><input type="submit" name="submit" value="                =                "></td>
    </tr>

</table>
</form>

答案 1 :(得分：5)

就个人而言，我会做一个开关，而不是所有这些，否则，如果，否则

$first = $_POST['first'] + 0;//a small "hack" to make sure its an int but allow negs!!
$second= $_POST['second'] + 0;
$operator = $_POST["group1"];
switch($operator)
{
    case "add"
    echo "Answer is: " .$first + $second;
    break; 
    case "subtract"
    echo "Answer is: " .$first - $second;
    break;
    case "times"
    echo "Answer is: " .$first * $second;
    break; 
    case "divide"
    echo "Answer is: " .$first / $second;
    break;
}

答案 2 :(得分：3)

您需要分配$ first和$ second 

$first = $_POST['first'];
$second= $_POST['second'];

另外，正如Travesty3所说，你需要在引号之外进行算术运算：

echo $first + $second;

答案 3 :(得分：3)

您还需要将[==＆＃39;添加＆＃39;]数学运算放入引号

if($_POST['group1'] == 'add') {
echo $first + $second;
}

完整的代码应该是这样的：

<?php
$first = $_POST['first'];
$second= $_POST['second'];
if($_POST['group1'] == 'add') {
echo $first + $second;
}
else if($_POST['group1'] == 'subtract') {
echo $first - $second;
}
else if($_POST['group1'] == 'times') {
echo $first * $second;
} 
else if($_POST['group1'] == 'divide') {
echo $first / $second;
}
?>

答案 4 :(得分：1)

您需要以相同的方式获取值，以获得计算器操作，如下所示：

<?php
if($_POST['group1'] == add) {
echo "$_POST['first']+ $_POST['second'];
}
... and so on
?>

或者，为了方便起见，请执行以下操作：

    <!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Answer</title>
</head>
<body>
<p>The answer is: 
<?php
$first = $_POST['first'];
$second= $_POST['second'];

if($_POST['group1'] == add) {
echo "$first + $second";
}
else if($_POST['group1'] == subtract) {
echo "$first - $second";
}
else if($_POST['group1'] == times) {
echo "$first * $second";
}
else($_POST['group1'] == divide) {
echo "$first / $second";
}
?>
</p> 
</body>
</html>

答案 5 :(得分：1)

$first = doubleval($_POST['first']);
$second = doubleval($_POST['second']);

if($_POST['group1'] == 'add') {
    echo "$first + $second = ".($first + $second);
}

// etc

答案 6 :(得分：0)

使用单引号检查字符串

实施例。 $_POST['group1'] == 'add'

答案 7 :(得分：0)

<?php
/**
 * The template for displaying the footer
 *
 * Contains the closing of the #content div and all content after
 *
 * @package WordPress
 * @subpackage Twenty_Sixteen
 * @since Twenty Sixteen 1.0
 */
?>
<style>
    @media screen and (min-width: 61.5625em){
        .content-area .site-main {
            margin-bottom: 0px;
        }
    }
</style>
    </div><!-- .site-content -->

    <footer id="colophon" class="site-footer" role="contentinfo">
        <?php if ( has_nav_menu( 'primary' ) ) : ?>
            <nav class="main-navigation" role="navigation" aria-label="<?php esc_attr_e( 'Footer Primary Menu', 'twentysixteen' ); ?>">
                <?php
                    wp_nav_menu( array(
                        'theme_location' => 'primary',
                        'menu_class'     => 'primary-menu',
                     ) );
                ?>
            </nav><!-- .main-navigation -->
        <?php endif; ?>

        <?php if ( has_nav_menu( 'social' ) ) : ?>
            <nav class="social-navigation" role="navigation" aria-label="<?php esc_attr_e( 'Footer Social Links Menu', 'twentysixteen' ); ?>">
                <?php
                    wp_nav_menu( array(
                        'theme_location' => 'social',
                        'menu_class'     => 'social-links-menu',
                        'depth'          => 1,
                        'link_before'    => '<span class="screen-reader-text">',
                        'link_after'     => '</span>',
                    ) );
                ?>
            </nav><!-- .social-navigation -->
        <?php endif; ?>

    </footer><!-- .site-footer -->
</div><!-- .site-inner -->

答案 8 :(得分：0)

  

在php文件中进行此更改

<html>
<head>
<meta charset="utf-8">
<title>Answer</title>
</head>
<body>
<p>The answer is: 
<?php
$first = $_POST['first'];
$second= $_POST['second'];
if($_POST['group1'] == 'add') {
echo $first + $second;
}
else if($_POST['group1'] == 'subtract') {
echo $first - $second;
}
else if($_POST['group1'] == 'times') {
echo $first * $second;
}

else if($_POST['group1'] == 'divide') {
echo $first / $second;
}
else {
    echo "Enter the numbers properly";
}
?>
</p> 
</body>
</html>

答案 9 :(得分：0)

<?php
$cal1= $_GET['cal1'];
$cal2= $_GET['cal2'];
$symbol =$_GET['symbol'];


if($symbol == '+')
{
    $add = $cal1 + $cal2;
    echo "Addition is:".$add;
}

else if($symbol == '-')
{
    $subs = $cal1 - $cal2;
    echo "Substraction is:".$subs;
}

 else if($symbol == '*')
{
    $mul = $cal1 * $cal2;
    echo "Multiply is:".$mul;
}

else if($symbol == '/')
{
    $div = $cal1 / $cal2;
    echo "Division is:".$div;
}

  else
{

    echo "Oops ,something wrong in your code son";
}


?>

答案 10 :(得分：0)

<!DOCTYPE html>
<html lang="en" dir="ltr">
    <head>
        <meta charset="utf-8">
        <title>Calculator</title> 
    </head>
<body>

    <form method="GET">
    <h1>Calculator</h1>
    <p>This is a calculator made by Hau Teen Yee Fabrice and is free to use.</p>
        <ul>
     <ol> Multiplication: * </ol>
     <ol> Substraction: - </ol>
     <ol> Division: / </ol>
     <ol> Addition: + </ol>
        </ul>
     <p>Enter first number:</p>
        <input type="text" name="cal1">
        <p>Enter second number:</p>
        <input type="text" name="cal2">
        <p>Enter the calculator symbol</p>
        <input type="text" name="symbol">
        <button>Calculate</button>
    </form>
    <?php
    $cal1= $_GET['cal1'];
    $cal2= $_GET['cal2'];
    $symbol =$_GET['symbol'];

    if($symbol == '+')
    {
        $add = $cal1 + $cal2;
        echo "Addition is:".$add;
    }
    else if($symbol == '-')
    {
        $subs = $cal1 - $cal2;
        echo "Substraction is:".$subs;
    }
     else if($symbol == '*')
    {
        $mul = $cal1 * $cal2;
        echo "Multiply is:".$mul;
    }
    else if($symbol == '/')
    {
        $div = $cal1 / $cal2;
        echo "Division is:".$div;
    }
      else
    { 
        echo "Oops ,something wrong in your code son";
    }
    ?>
    </body> 
</html>
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