Question

我正在尝试从ReactiveList中压缩两个序列，以便在更改内容时返回旧值和新值。但是，压缩订阅似乎返回了“旧的和新的”相同的值。

我错过了什么？

谢谢： - ）

void Main()
{
    var names = new string[] {"Bill","Jane","Tom", "Jess"};
    var list = new ReactiveList<ReactivePerson>(){ChangeTrackingEnabled = true};


    // These subscriptions work as expected
    list.ItemChanging.Subscribe(x=> string.Format("Property {0} changing from {1}",x.PropertyName, x.GetValue()).Dump());
    list.ItemChanged.Subscribe(x=> string.Format("Property {0} changed to {1}",x.PropertyName, x.GetValue()).Dump());

    // This subscription doesn't. It is returning the same value for both 'old and new'
    list.ItemChanging.Zip(list.ItemChanged, (oldrec, newrec)=>new{o=oldrec.GetValue(),n=newrec.GetValue()}).Subscribe(x=>x.Dump());

    // Add records
    list.AddRange(names.Select (n => new ReactivePerson{FirstName=n}));

    // manipulate records
    list[0].FirstName = "Terry";
}

public class ReactivePerson : ReactiveObject
{
        string _firstName;
        public string FirstName{
            get { return _firstName; }
            set { this.RaiseAndSetIfChanged(ref _firstName, value); }
        }
}

Answer 1

嗯，这应该有效，我怀疑ReactiveList中有拼写错误。想为它创建一个测试用例吗？

麻烦压缩ReactiveList <t> .ItemChanging with ReactiveList <t> .ItemChanged </t> </t>

1 个答案: