Question

我正在尝试创建一个动态嵌套菜单，并遇到一些我不知道如何处理的问题。在每个顶级菜单项之后，我得到一个空的UL标签集。此外，当存在下拉菜单时，LI标签集未正确包装UL标签。

这是我试图修改的代码....谢谢！

$sql = "SELECT menuID, menuTitle, menuURL, menuParentID, menuOrderID FROM menu ORDER BY menuParentID, menuOrderID ASC";
$items = mysql_query($sql);
while ($obj = mysql_fetch_object($items)) {
    if ($obj->menuParentID == 0) {
        $parent_menu[$obj->menuID]['menuTitle'] = $obj->menuTitle;
        $parent_menu[$obj->menuID]['link'] = $obj->menuURL;
    } else {
        $sub_menu[$obj->menuID]['parent'] = $obj->menuParentID;
        $sub_menu[$obj->menuID]['menuTitle'] = $obj->menuTitle;
        $sub_menu[$obj->menuID]['link'] = $obj->menuURL;
        if (!isset($parent_menu[$obj->menuParentID]['count'])) {
            $parent_menu[$obj->menuParentID]['count'] = 0;
        }
        $parent_menu[$obj->menuParentID]['count']++;
    }
}
mysql_free_result($items);



function dyn_menu_folded($parent_array, $sub_array, $qs_val = "menu", $main_id = "nav", $sub_id = "dropdown-menu", $dd_style = "dropdown") {
    $menu = "<ul class=\"".$main_id."\">\n";
    foreach ($parent_array as $pkey => $pval) {
        if (!empty($pval['count'])) {
            $menu .= "  <li class=\"".$dd_style."\"><a href=\"".$pval['link']./*"?".$qs_val."=".$pkey.*/"\">".$pval['menuTitle']."<b class=\"caret\"></b></a></li>\n";
        } else {
            $menu .= "  <li><a href=\"".$pval['link']."\">".$pval['menuTitle']."</a></li>\n";
        }
        //if (!empty($_REQUEST[$qs_val])) {
        $menu .= "<ul class=\"".$sub_id."\">\n";
        foreach ($sub_array as $sval) {
            if ($pkey == $sval['parent']) { //
                $menu .= "<li><a href=\"".$sval['link']."\">".$sval['menuTitle']."</a></li>\n";
            }
        }
        $menu .= "</ul>\n";
        //}
    }
    $menu .= "</ul>\n";
    return $menu;
}

?>
<?php
echo dyn_menu_folded($parent_menu, $sub_menu, "menu", "nav", "dropdown-menu");
?>




//this is a sample of the result.

<ul class="nav">
    <li ><a href="#">ITEM A</a></li>
<ul class="dropdown-menu"></ul>  //IMPROPER UL TAGS
    <li ><a href="#">ITEM B</a></li>
<ul class="dropdown-menu"></ul>
    <li ><a href="#">ITEM C</a></li>
<ul class="dropdown-menu"></ul>
    <li ><a href="#">ITEM D</a></li>
<ul class="dropdown-menu"></ul>
    <li class="dropdown"><a href="#">ITEM E<b class="caret"></b></a>
    </li> //LI TAG NOT WRAPPING AROUND UL TAG
        <ul class="dropdown-menu">
            <li ><a href="#">ITEM E1</a></li>
            <li ><a href="#">ITEM E2</a></li>
            <li ><a href="#">ITEM E3</a></li>
            <li ><a href="#">ITEM E4</a></li>
            <li ><a href="#">ITEM E5</a></li>
        </ul>
    <li class="dropdown"><a href="#">ITEM F<b class="caret"></b></a>
    </li>
        <ul class="dropdown-menu">
            <li ><a href="#">ITEM F1</a></li>
            <li ><a href="#">ITEM F2</a></li>
            <li ><a href="#">ITEM F3</a></li>
            <li ><a href="#">ITEM F4</a></li>
            <li ><a href="#">ITEM F5</a></li>
            <li ><a href="#">ITEM F6</a></li>
        </ul>
    <li ><a href="#">ITEM G</a></li>
<ul class="dropdown-menu"></ul>
    <li ><a href="#">ITEM H</a></li>
<ul class="dropdown-menu"></ul>
    <li ><a href="#">ITEM I</a></li>
<ul class="dropdown-menu"></ul>
    <li ><a href="#">ITEM J</a></li>
<ul class="dropdown-menu"></ul>
</ul>


//This is how it should look.

<ul class="nav">
    <li ><a href="#">ITEM A</a></li>
    <li ><a href="#">ITEM B</a></li>
    <li ><a href="#">ITEM C</a></li>
    <li ><a href="#">ITEM D</a></li>
    <li class="dropdown"><a href="#">ITEM E<b class="caret"></b></a>
        <ul class="dropdown-menu">
            <li ><a href="#">ITEM E1</a></li>
            <li ><a href="#">ITEM E2</a></li>
            <li ><a href="#">ITEM E3</a></li>
            <li ><a href="#">ITEM E4</a></li>
            <li ><a href="#">ITEM E5</a></li>
        </ul>
    </li>
    <li class="dropdown"><a href="#">ITEM F<b class="caret"></b></a>
        <ul class="dropdown-menu">
            <li ><a href="#">ITEM F1</a></li>
            <li ><a href="#">ITEM F2</a></li>
            <li ><a href="#">ITEM F3</a></li>
            <li ><a href="#">ITEM F4</a></li>
            <li ><a href="#">ITEM F5</a></li>
            <li ><a href="#">ITEM F6</a></li>
        </ul>
    </li>
    <li ><a href="#">ITEM G</a></li>
    <li ><a href="#">ITEM H</a></li>
    <li ><a href="#">ITEM I</a></li>
    <li ><a href="#">ITEM J</a></li>
</ul>

Answer 1

如果不确定$ parent_menu和$ sub_menu是如何构建的，我不能确定这是否可以完成这项工作，但无论如何都要试一试。

function create_menu($parent_array, $sub_array, $qs_val = "menu", $main_id = "nav", $sub_id = "dropdown-menu", $dd_style = "dropdown")
{
    $menu = "<ul class=\"{$main_id}\">\n";

    foreach ($parent_array as $pkey => $pval) {
        if ( ! empty($pval['count'])) {
            $menu .= "\t<li class=\"{$dd_style}\"><a href=\"{$pval['link']}\">{$pval['menuTitle']}<b class=\"caret\"></b></a>\n";
            $menu .= "\t\t<ul class=\"{$sub_id}\">\n";

            foreach ($sub_array as $sval) {
                if ($pkey == $sval['parent']) {
                    $menu .= "\t\t\t<li><a href=\"{$sval['link']}\">{$sval['menuTitle']}</a></li>\n";
                }
            }

            $menu .= "</ul></li>\n";
        } else {
            $menu .= "\t<li><a href=\"{$pval['link']}\">{$pval['menuTitle']}</a></li>\n";
        }
    }

    return $menu . "</ul>\n";
}

如果您仍有问题，请发布$ parent_menu和$ sub_menu的var_dump（）输出。

动态嵌套菜单包含错误的<ul>标记，<li>不包围子菜单项</li> </ul>

1 个答案: