我成功地在这样的元素上移动数组中的路径:
var c = Raphael("canvas", 500, 500);
var p = c.path("most code").attr({
fill: '#33CCFF',
stroke: '#000000',
'stroke-width': 5
});
var times = [most code];
var paths = [most code];
var current=0;
function nextStep(){
if (current>paths.length)
return;
p.animate({
path: paths[current]
}, times[current++],nextStep);
}
nextStep();
但是我会通过包含路径的组的数组做同样的事情,我尝试了相同的方式,但是将组放在数组中,我需要成组,因为每个组都会告诉数百个到该元素的路径。 / p>
var rsr = Raphael('rsr', '500', '500');
// frame 1
var path3184 = rsr.path("most code").attr({
"fill-rule": 'evenodd',
"clip-rule": 'evenodd',
fill: '#8FC876',
id: 'path3184',
parent: 'g3182',
'stroke-width': '0',
'stroke-opacity': '1'
}).data('id', 'path3184');
// frame 2
var path3186 = rsr.path("most code").attr({
"fill-rule": 'evenodd',
"clip-rule": 'evenodd',
fill: '#2FA990',
id: 'path3186',
parent: 'g3182',
'stroke-width': '0',
'stroke-opacity': '1'
}).data('id', 'path3186');
// group 1
var g3182 = rsr.set();
g3182.push(
path3184
);
// group 2
var g3183 = rsr.set();
g3183.push(
path3186
);
// load next group function
var paths = [g3182, g3183];
var times = [1000, 1000];
var current=0
function nextStep(){
if (current>paths.length)
return;
rsr.animate({
path: paths[current]
}, times[current++],nextStep);
}
nextStep();
答案 0 :(得分:1)
我认为您只需更改一行:
rsr.animate({
至
g3182.animate({
(或者您希望制作动画的组。)