Question

在此表中：

|value_id|entity_type_id|attribute_id|store_id|entity_id|value
|9289729 |4             |62          |0       |765985   |default value
|9289730 |4             |62          |1       |765985   |value in spanish
|9289731 |4             |62          |2       |765985   |value in dutch

如果不存在，我需要获取store_id的值（可以是1,2或3）或默认值（store_id = 0）。
并且它必须包含在由几个INNER JOINS组成的更大的查询中，到目前为止看起来像这样：

SELECT DISTINCT `p2c`.`product_id`, `name_id`.`value` AS `name`, `short_description_id`.`value` AS `short_description` FROM `catalog_category_product` AS `p2c`
 INNER JOIN `catalog_product_entity_int` AS `status` ON p2c.product_id = status.entity_id AND status.value = 1
 INNER JOIN `catalog_product_entity_int` AS `visibility` ON p2c.product_id = visibility.entity_id AND visibility.value = 4
 INNER JOIN `catalog_product_entity_varchar` AS `name_id` ON p2c.product_id = name_id.entity_id AND name_id.attribute_id = 60
 INNER JOIN `catalog_product_entity_text` AS `short_description_id` ON p2c.product_id = short_description_id.entity_id AND short_description_id.attribute_id = 62
WHERE (category_id IN ('1224'))

所以我想要的是：

SELECT DISTINCT `p2c`.`product_id`, `name_id`.`value` AS `name`, `short_description_id`.`value` AS `short_description` FROM `catalog_category_product` AS `p2c`
 INNER JOIN `catalog_product_entity_int` AS `status` ON p2c.product_id = status.entity_id AND status.value = 1
 INNER JOIN `catalog_product_entity_int` AS `visibility` ON p2c.product_id = visibility.entity_id AND visibility.value = 4
 INNER JOIN `catalog_product_entity_varchar` AS `name_id` ON p2c.product_id = name_id.entity_id AND name_id.attribute_id = 60
 INNER JOIN `catalog_product_entity_text` AS `short_description_id` ON p2c.product_id = short_description_id.entity_id 
 AND short_description_id.attribute_id = 62
//start of not real mysql code
 AND ((short_description_id.store_id = 3) IF THERE IS A VALUE FOR THIS STORE_ID
      OR (short_description_id.store_id = 0) OTHERWISE)
//end of not real mysql code
WHERE (category_id IN ('1224'))

哦，如果重要的话，我正在使用Zend的mysql 有什么想法吗？

Answer 1

一种方法是将join两次保留到catalog_product_entity_text。一次用于ID 0，另一次用于ID 3，然后在选择

中执行COALESCE

SELECT
..
 COALESCE(`short_description_id`.`value` , `short_description_id_DEFAULT`.`value`) AS `short_description`
..
FROM 
...

     LEFT JOIN `catalog_product_entity_text` AS `short_description_id` 
     ON p2c.product_id = short_description_id.entity_id 
         AND short_description_id.attribute_id = 62
         AND (short_description_id.store_id = 3)

     LEFT JOIN `catalog_product_entity_text` AS `short_description_id_DEFAULT` 
     ON p2c.product_id = short_description_id.entity_id 
         AND short_description_id.attribute_id = 62
         AND (short_description_id.store_id = 0)

如果存在则选择一个值，否则选择另一个值

1 个答案: