Question

我不明白这个功能的错误是为了得到我的authkey？我只得到这个名为“invalid_request”的错误，有没有人有任何想法？好像不明白我的要求？

// Innk

public partial class OAuth : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)

    {

string _clientID = HttpUtility.UrlEncode("***********");

        string _clientSecret = HttpUtility.UrlEncode("******");

        string _redirectUri = "urn:ietf:wg:oauth:2.0:oob";

        string _code = HttpUtility.UrlEncode("token");

        string url = "code=" + _code + "&client_id=" + _clientID + "&client_secret=" + _clientSecret + "&redirect_uri=" + _redirectUri + "&grant_type=urn:ietf:params:oauth:grant-type:jwt-bearer";

        TcpClient client = new TcpClient("accounts.google.com", 443);
        Stream netStream = client.GetStream();
        SslStream sslStream = new SslStream(netStream);
        sslStream.AuthenticateAsClient("accounts.google.com");
        {
            byte[] contentAsBytes = Encoding.ASCII.GetBytes(url.ToString());
            StringBuilder msg = new StringBuilder();
            msg.AppendLine("POST /o/oauth2/token HTTP/1.1");
            msg.AppendLine("Host: accounts.google.com");
            msg.AppendLine("Content-Type: application/x-www-form-urlencoded");
            msg.AppendLine("Content-Length: " + contentAsBytes.Length.ToString());
            msg.AppendLine("");
            Debug.WriteLine("Request");
            Debug.WriteLine(msg.ToString());
            Debug.WriteLine(url.ToString());
            byte[] headerAsBytes = Encoding.ASCII.GetBytes(msg.ToString());
            sslStream.Write(headerAsBytes);
            sslStream.Write(contentAsBytes);
        }
        Debug.WriteLine("Response");
        StreamReader reader = new StreamReader(sslStream);
        while (true)
        {  // Print the response line by line to the debug stream for inspection.
            string line = reader.ReadLine();
            if (line == null)
                break;
            Debug.WriteLine(line);
        }

    }
}

Answer 1

我强烈建议任何进行.NET开发并希望访问YouTube API的人使用official client library。

如果您不想将客户端库用于所有操作，至少，我建议您将它用于handle OAuth 2，然后使用它在{{1}中生成的令牌你自己滚动的请求的标题。

Oauth2 YouTube“错误”：“invalid_request”

1 个答案: