MySQL查询，来自数据的十大结果，并计算其下​​的内容

Question

这是我的查询，我得到了前15名的结果，一切都没问题，但前15名下面有很多行，我需要收集那些 结果，计算它们并在同一查询中将其命名为“其他”。以下是我得到的结果和查询：

SELECT  `Person` , COUNT(  `Person` ) AS Total
FROM taxes
WHERE  `Person` IS NOT NULL 
AND  `Person` <>  ''
AND  `Date` 
BETWEEN  '2013-11-11'
AND  '2013-11-30'
GROUP BY (
 `Person`
)
ORDER BY  `Total` DESC 
LIMIT 5

结果

Person - Total

a ------ 66     
b ------ 44
c ------ 33
d ------ 13
e ------ 14
-----------
f ------ 10
g ------ 8
h ------ 7

以下是我想要的内容：

Person | Total
a ------ 66     
b ------ 44
c ------ 33
d ------ 13
e ------ 14
-----------
others --- 25

谢谢！

Answer 1

使用联盟，限制和抵消

SQLFiddle： http://sqlfiddle.com/#!2/69e65/1

(SELECT `Person` ,
 COUNT(`Person`) AS `Total`
 FROM taxes
 WHERE `Person` IS NOT NULL
 AND `Person` <> ''
 AND `Date` BETWEEN '2013-11-11' AND '2015-11-30'
 GROUP BY `Person`
 ORDER BY COUNT(`Person`) DESC LIMIT 2)
UNION
 (SELECT 'Other',
 sum(`Total`) AS `Total`
 FROM
 ( SELECT `Person` ,
 COUNT(`Person`) AS Total
 FROM taxes
 WHERE `Person` IS NOT NULL
 AND `Person` <> ''
 AND `Date` BETWEEN '2013-11-11' AND '2015-11-30'
 GROUP BY `Person`
 ORDER BY COUNT(`Person`) DESC 
 LIMIT 2, 18446744073709551615) AS TEMP 
 );

使用@row变量

SQLFiddle： http://sqlfiddle.com/#!2/0a61a/5

set @row:=1;
select if(@row>2, 'Other', `Person`) as `Person`,
sum(`Total`) as `Total`,
@row:=@row+1 as `IgnoreColumn` 
from
(
 SELECT `Person` ,
 COUNT(`Person`) AS Total
 FROM taxes
 WHERE `Person` IS NOT NULL
 AND `Person` <> ''
 AND `Date` BETWEEN '2013-11-11' AND '2015-11-30'
 GROUP BY `Person`
 ORDER BY COUNT(`Person`) DESC
) as TEMP
group by if(@row>2, 'Other', `Person`)
order by @row;