Question

我有以下两个数组：

$cars = array("BMW", "VW", "Kia", "Ford", "Ferrari", "Lamborghini"); 

$for_sale = array(
  array(
   "engine_capacity" => "1600",
   "car_id" => 5,
   "year" => 1937),
  array(
   "engine_capacity" => "2400",
   "car_id" => 0,
   "year" => 1937),
  array(
   "engine_capacity" => "2000",
   "car_id" => 3,
   "year" => 1937),
  array(
   "engine_capacity" => "2000",
   "car_id" => 4,
   "year" => 1937),
  array(
   "engine_capacity" => "4800",
   "car_id" => 2,
   "year" => 1937),
  array(
   "engine_capacity" => "6000",
   "car_id" => 1,
   "year" => 1937),
);

我正在尝试将$ cars中的索引与$ for_sale中的'car_id'值匹配，然后显示匹配的汽车名称。即“car_id”=＆gt; 0将显示BMW等。我看过各种类似的问题，但是他们帮助很小。任何帮助都会非常感激，因为我在这项任务中一直都很失败。 Thankx。

Answer 1

如果要合并两个数组，为了在car_id数组中包含car_name和$for_sale，请尝试使用：

for($i = 0; $i < count($cars) && $i < count($for_sale); $i++) {
    $for_sale[$i]['car_name'] = $cars[$i];
}

var_dump($for_sale);

<强> PHP Fiddle

Answer 2

检查

for($i = 0; $i < count($cars) && $i < count($for_sale); $i++) {
        $for_sale[$i]['car_id'] = $cars[$i];
    }

    var_dump($for_sale);

将$for_sale[$i]['car_name']更改为$for_sale[$i]['car_id']您将获得正确的结果现在[0]将是宝马的索引等等。

Answer 3

你的意思是你想根据car_id输出汽车的价值，其中car_id是汽车的索引，如：

echo $cars[$for_sale[1]['car_id']]

这应该回应BMW

修改

显示所有待售的车名，这将是一种方法：

foreach($for_sale as $fs) { if (isset($cars[$fs['car_id']])) { echo $cars[$fs['car_id']]; } }

Answer 4

**使用此代码工作.. **

foreach($for_sale as $k =>$v){
  foreach($cars as $key => $val){
     if($for_sale[$k]['car_id'] == $key){
       echo $cars[$key]; 
     }
  }       
}

解决此问题的另一种方法是：

foreach($for_sale as $k =>$v){
  $for_sale[$k]['car_name'] = $cars[$v['car_id']];
}

将多维数组中的值与另一个数组的索引进行比较

4 个答案: