我写了下面的代码;当我在下拉列表相关的文本文件中选择包含某些内容的India/America
时,必须在div
元素中读取并显示,但在行xhr.send()
中出现错误
谁能解释为什么?
<html>
<head>
<script>
function getcity()
{
var a=document.getElementById("country");
var b=a[a.selectedIndex].value;
alert(b);
var xhr=new XMLHttpRequest();
if(b=="India")
{
xhr.onreadystatechange=function()
{
if((xhr.readystate==4)&&(xhr.status==200||xhr.status==304))
{
document.getElementByID("display").innerHTML=xhr.responseText;
}
}
xhr.open("GET","india.txt",true);
}
else
{
xhr.onreadystatechange=function()
{
if((xhr.readystate==4)&&(xhr.status==200||xhr.status==304))
{
document.getElementByID("display").innerHTML=xhr.responseText;
}
}
xhr.open("GET","america.txt",true);
}
xhr.send(null);
}
</script>
</head>
<body>
<select id="country" onchange="getcity()">
<option>India</option>
<option>America</option>
</select>
<div id="display"></div>
</body>
</html>
答案 0 :(得分:0)
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script>
function getcity()
{
var a=document.getElementById("country");
var b=a[a.selectedIndex].value;
alert(b);
var xhr=new XMLHttpRequest();
if(b=="India")
{
xhr.onreadystatechange=function()
{
if((xhr.readystate==4)&&(xhr.status==200||xhr.status==304))
{
document.getElementByID("display").innerHTML=xhr.responseText;
}
}
xhr.open("GET","india.txt",true);
}
else
{
xhr.onreadystatechange=function()
{
if((xhr.readystate==4)&&(xhr.status==200||xhr.status==304))
{
document.getElementByID("display").innerHTML=xhr.responseText;
}
}
xhr.open("GET","america.txt",true);
}
xhr.send(null);
}
</script>
</head>
<body>
<select id="country" onchange="getcity()">
<option>India</option>
<option>America</option>
</select>
<div id="display"></div>
</body>
</html>