如何通过Google Closure Compiler Advance模式解除运行以下代码的警告?
var defaults = {
team : 'ABC',
wr: 'Calvin',
qb: 'Manning'
};
var config = {};
var setters = {
team : function(){ return defaults.team},
wr : function(){ return defaults.wr}
};
for(var i in setters){
config[i] = setters[i].call();
}
alert( config.team);
alert( config.wr);
警告数量:2
JSC_INEXISTENT_PROPERTY: Property team never defined on config at line 19 character 7
alert(config.team);
^
JSC_INEXISTENT_PROPERTY: Property wr never defined on config at line 20 character 7
alert(config.wr);
^
答案 0 :(得分:2)
找到它。
@lends就可以了。
var defaults = {
team : 'ABC',
wr: 'Calvin',
qb: 'Manning'
};
var config = {};
var setters =
/** @lends {config} */
{
team : function(){ return defaults.team},
wr : function(){ return defaults.wr}
};
for(var i in setters){
config[i] = setters[i].call();
}
alert(config.team);
alert(config.wr);
答案 1 :(得分:0)
我猜你应该用null值定义这些属性,因此编译器会知道它。
var config = {
team: null,
wr: null
};
建议编号2(我不确定):尝试注释配置类型。像这样:
/** @type {{team: *, wr: *}} */
var config = {};
OR 使用clone:
var config = goog.object.clone(setters);
goog.object.forEach(config, function(val, key) {
config[key] = val.call();
});
答案 2 :(得分:0)
作为替代方案,您可以将类型注释为更通用:
/** @type {Object} */ var config = {}; // allow any prop defined anywhere on any object.
或更具体:
/** @type {{team:(string|undefined), wr:(string|undefined), qb:(string|undefined)}} */ var config = {}; // "team", "wr" and "qb" are expected.