Question

我正在尝试创建用户，并且所有值都未插入数据库。 systems_user表与party表有关系，因为party_id是sytems_user的主键。什么都没有插入。甚至不是错误，它只是回到“创建”页面。这是我的架构：

--
-- Table structure for table `system_users`
--

CREATE TABLE IF NOT EXISTS `system_users` (
  `party_id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
  `username` varchar(200) NOT NULL,
  `password` varchar(255) NOT NULL,
  `date_last_login` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `status` varchar(50) NOT NULL DEFAULT 'Pending for Approval',
  `date_created` datetime NOT NULL,
  `date_modified` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `user_role` varchar(255) NOT NULL,
  `isLogin` int(1) NOT NULL,
  PRIMARY KEY (`party_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=221 ;

--
-- Constraints for table `system_users`
--
ALTER TABLE `system_users`
  ADD CONSTRAINT `system_users_ibfk_1` FOREIGN KEY (`party_id`) REFERENCES `parties` (`id`);

-------------------------------------
-- Table structure for table `parties`
--

 CREATE TABLE IF NOT EXISTS `parties` (
   `id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
   `party_type_id` int(10) unsigned NOT NULL,
   PRIMARY KEY (`id`),
  KEY `party_type_id` (`party_type_id`)
 ) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=200 ;

--
-- Constraints for table `parties`
--
ALTER TABLE `parties`
  ADD CONSTRAINT `parties_ibfk_1` FOREIGN KEY (`party_type_id`) REFERENCES `party_types`    (`id`);

我哪里出错了？为什么不插入？

修改

SystemUser Model的规则：

public function rules()
{
    // NOTE: you should only define rules for those attributes that
    // will receive user inputs.
    return array(
        array('username, password, date_last_login, date_created, user_role, isLogin', 'required'),
        array('isLogin', 'numerical', 'integerOnly'=>true),
        array('username', 'length', 'max'=>200),
        array('password, user_role', 'length', 'max'=>255),
        array('status', 'length', 'max'=>50),
        array('date_modified', 'safe'),
        // The following rule is used by search().
        // Please remove those attributes that should not be searched.
        array('party_id, username, password, date_last_login, status, date_created, date_modified, user_role, isLogin', 'safe', 'on'=>'search'),
    );
}

缔约方规则：

 public function rules()
{
    // NOTE: you should only define rules for those attributes that
    // will receive user inputs.
    return array(
        array('party_type_id', 'required'),
        array('party_type_id', 'length', 'max'=>10),
        // The following rule is used by search().
        // Please remove those attributes that should not be searched.
        array('id, party_type_id', 'safe', 'on'=>'search'),
    );
}

EDIT Controller actionCreate（）

一点背景：从下面可以看出，if语句中的条件只是询问SystemUsers是否已设置，因为create来自SystemUser表单。我的目标是获取system_user的party_id并将其插入到Parties表中，该表与我正在使用的SystemUsers不同。到目前为止，当我运行它时，没有任何反应。

public function actionCreate()
{
    $parties = new Parties;
    $model= new SystemUsers;

    // Uncomment the following line if AJAX validation is needed
    // $this->performAjaxValidation($model);

     if (isset($_POST['SystemUsers']))
            {
                $parties->attributes = (HOW can I put the party_id from $model here?);
                $model->attributes = $_POST['SystemUsers'];
                $valid = true; 
                $valid &= $parties->validate(); 
                $valid &= $model->validate(); 

                if($valid)
                    {
                        $parties->id = $model->getPrimaryKey();
                        $parties->save(); /* First save parties. */

                        $model->save(); 
                    }
            } 

    $this->render('create',array(
    'model'=>$model,
    'parties'=>$parties, 
    ));

Answer 1

Yii 不会在数据库中插入不安全的值，之前我遇到过此问题，如果您确保所有属性安全，那么会没事的。您的属性现在仅在search方案（'on'=>'search'）中是安全的。要在所有方案中使所有属性都安全，请从两个模型规则中删除'on'=>'search'。
您在 $parties->id = $customers->getPrimaryKey();之后放置了$parties->save(); 。

如果您想保存$parties->id，请将其放在save()

之前

删除redirect行，我认为您的save()方法无法显示错误。

更新：

这个怎么样？

if (isset($_POST['SystemUsers'])) { $model->attributes = $_POST['SystemUsers']; if($model->save()){ // save() does validation in itself $parties->id = $model->getPrimaryKey(); $parties->save(); } }

SQL没有在Yii中插入关系表

1 个答案: