Question

这是PHP代码：您需要使用参数methode = getAll：

进行POST调用

$ filters = array（）; $ filters ['denomination'] ='T％';

    $param = array(
     'type_element' => 'personne_morale',
     'order' => 'denomination',
     'limit' => 2,
     'filtres' => $filters
     );

这是我的ios代码无效，它会给出错误：

NSError *错误;

        NSURL *url = [NSURL URLWithString: @"https://www.eden-pme.com/edensoft/edenfiles/edensoft2014/api.php"];
        NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];




        NSURLResponse *response;

        NSString *postString;
        postString = [NSString stringWithFormat:@"api_public_key:api_private_key,6c8a4cf9044e48e4383b9f6a8f400055:94a337a9dd6fb58f5004f244187d5d39"];


        [request setURL:url];
        [request setHTTPMethod:@"POST"];
        [request setValue:postString forHTTPHeaderField:@"Content-Type"];
       // NSURLResponse *response;
        NSData *res = [NSURLConnection  sendSynchronousRequest:request returningResponse:&response error:&error];

        NSArray *jsonArr = [NSJSONSerialization JSONObjectWithData:res options:kNilOptions error:&error];
            NSLog(@"%@",jsonArr);

Answer 1

NSString * urlAsStr = @“https://www.eden-pme.com/edensoft/edenfiles/edensoft2014/api.php”;

NSMutableDictionary *dict = [[NSMutableDictionary alloc]init];
[dict setObject:@"6c8a4cf9044e48e4383b9f6a8f400055" forKey:@"PHP_AUTH_USER"];
[dict setObject:@"94a337a9dd6fb58f5004f244187d5d39" forKey:@"PHP_AUTH_PW"];
[dict setObject:@"getAll" forKey:@"methode"];
[dict setObject:@"denomination" forKey:@"order"];
//[dict setObject:@"2" forKey:@"limit"];
[dict setObject:@"personne_morale" forKey:@"type_element"];
[dict setObject:@"1" forKey:@"return_array"];

NSString *stringJson = [[[NSString alloc] initWithData:[NSJSONSerialization dataWithJSONObject:dict options:0 error:nil] encoding:NSUTF8StringEncoding] autorelease];

NSString *postString = [NSString stringWithFormat:@"param=%@",stringJson];
NSData *postData = [postString dataUsingEncoding:NSUTF8StringEncoding];


NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:urlAsStr]];
[request setHTTPMethod:@"POST"];
[request addValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

[request setHTTPBody:postData];


NSURLResponse *response;
NSError *err;
NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err];

dataArray = [NSJSONSerialization JSONObjectWithData：urlData options：kNilOptions error：＆amp; err];

Answer 2

试试这个，

将[request setValue:postString forHTTPHeaderField:@"Content-Type"];更改为

[request setHTTPBody:[postString dataUsingEncoding:NSUTF8StringEncoding]];

添加curl parmeter CURLOPT_USERPWD IOS

2 个答案: