Question

我有一张如下表格

Item Name | Date       | Previous Data | Updated Data
Unit 1    | 1-Jul-2013 | 500           | 550 
Unit 1    | 1-Aug-2013 | 550           | 550
Unit 1    | 1-Sep-2013 | 450           | 600 
Unit 1    | 1-Oct-2013 | 600            | 550

我希望使用查询显示它们，如下所示

Title     | Jul | Aug   | Sep | Oct
Prev. Data| 500 | 550   | 450 | 600
Upd. Data | 550 | 550   | 600 | 550

之前我使用UNION确保表格符合我的要求，但我想知道是否有更简单的方法。

我正在使用SQL Server 2008 R2

Answer 1

首先，您需要将2列[Previous Data]和[Updated Date]转换为行，然后才能在PIVOT列上使用Date

Select col,
[1] as Jan,
[2] Feb,
[3] Mar,
[4] Apr,
[5] May,
[6] Jun,
[7] Jul,
[8] Aug,
[9] Sep,
[10] Oct,
[11] Nov,
[12] Dec
from 
(
  select month(Date) as TMonth, col, value
  from Table1
  cross apply
  (
    select 'Previous Data', [Previous Data]
    union all
    select 'Updated Date', [Updated Data]
  ) c(col, value)
)a
PIVOT
(
 Sum(value)
 for Tmonth in ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12])
)pvt

SQL FIDDLE DEMO

Answer 2

请试试这个........

select 'PreviousData' as Title,Jul,Aug,Sep,Oct from
(
select a.itemname,left(datename(mm,convert(date,a.date)),3) [date]
 ,a.previousdata from @tab a
 ) srs
 pivot
 (
 sum(previousdata) for [date] in (jul,aug,sep,oct)
 ) pt
union all
 select 'UpdatedData' as Title,Jul,Aug,Sep,Oct from
(
select a.itemname,left(datename(mm,convert(date,a.date)),3) [date]
 ,a.Updateddata from @tab a
 ) srs
 pivot
 (
 sum(Updateddata) for [date] in (jul,aug,sep,oct)
 ) pt

如何在新行中显示查询结果

2 个答案: