Question

我似乎无法从此脚本获得任何响应。没有错误消息，没有......正如你所看到的，我想要做的是插入表“yum”，回显最后一个条目，然后使用最后一个条目插入一个单独的表。我做错了什么，为什么没有错误消息？

<?php
$b= $_GET["sto"];
$pb= $_GET["usto"];
$sql = "INSERT INTO yum(vara, varb) 
     VALUES('" . $b . "', '" . $pb . "')";

$hostname_Database = "blocked";
$database_Database = "blocked";
$username_Database = "blocked";
$password_Database = "blocked";

$mysqli = new mysqli($hostname_Database, $username_Database, $password_Database, $database_Database); 
if (mysqli_connect_errno()) {
   printf("Connect failed: %s\n", mysqli_connect_error());
   exit();
}



$result = $mysqli->query($sql);
if ($result) {

echo "ha";


$sql = $mysqli->query("SELECT vara FROM yum ORDER BY vara DESC LIMIT 1");

if($sql === FALSE) {
echo "ahahahahah";
    die(mysql_error()); // TODO: better error handling
}

while($row = mysql_fetch_array($sql))
{
    echo $row['vara'];
}



//$row = $result->fetch_assoc();

$sql = "INSERT INTO disco(varb, vara) 
     VALUES( '" . $item . "',  {$row['vara']})";
$result = $mysqli->query($sql);
if ($result) {


etc...


}
}
?>

Answer 1

您正在使用

while($row = mysql_fetch_array($sql))
{
echo $row['vara'];
}

这里当$ row对于最后一个条目变为null时所以使用foreach但是因为你只得到一行而不是所有的while循环只需使用

$row = mysql_fetch_array($sql);

也可以只使用mysql_ *或mysqli _ *

这是完整的代码

 $mysqli = mysqli_connect($hostname_Database, $username_Database, $password_Database, $database_Database); 
 if (mysqli_connect_errno($mysqli)) {
      printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
     }



 $result = $mysqli_query($con,$sql);
 if ($result) {

   echo "ha";


   $sql = $mysqli_query("SELECT vara FROM yum ORDER BY vara DESC LIMIT 1");

无法从mysql中检索最后一行

1 个答案: