Question

我只是盯着python，我认为做一个小测验会很有趣。我遇到的问题是，当你考虑到国会大厦的字母和字母时，有很多可能的答案。常见的拼写错误。我想说明这些，但没有'elif'功能的堆栈。有没有办法将所有可能的答案都放到一行？类似于||的东西在C. 代码示例：

y = input("Where was the 2004 Olympics held? ")
if y == "Athens":
    print ("Correct!")
    score = score + 1

但允许'athens'或'Greece'作为答案

Answer 1

你想要的是：

answer = input("Where was the 2004 Olympics held? ")
if answer.lower() in ("athens", "greece"):
    print ("Correct!")
    score = score+1

我也在降低答案，所以情况无关紧要！

N.B。：建立一个测验，这就是我的方法：

qas = {
    'Where was the 2004 Olympics held?': ['athens', 'greece'],
    'What is the answer of the question about life, the universe and everything?': ['42', 'forty-two'] 
    …
}

for q, a in qas:
    ans = input(q)
    if ans.lower() in a:
        print("Correct!")
        score += 1

Answer 2

if y.lower() in ["athens", "greece"]:
    print("Correct!")

Answer 3

烨！

只是做：

if y in ["athens", "blah", "other",...]:
    print ("Correct!")
    score += 1

Answer 4

y = input("Where was the 2004 Olympics held? ")
if y in ["Athens","Greece"]:
    print ("Correct!")
    score = score+1

多种可能的输入

4 个答案: