我有这条SQL指令(由其他人提供)
FROM P INNER JOIN
C ON P.p1 = C.p1 INNER JOIN
G INNER JOIN
U ON G.u1 = U.u1 ON
C.c1 = G.c1 INNER JOIN
R ON P.r1 = R.r1 INNER JOIN
F ON U.f1 = F.f1 RIGHT OUTER JOIN
UN ON U.u1 = UN.u1
我怎么读这一切?第2,第3,第4和第5行如何工作?
答案 0 :(得分:3)
通过一些格式化,我认为它变得更容易:
FROM P INNER JOIN C
ON P.p1 = C.p1
INNER JOIN G
INNER JOIN U
ON G.u1 = U.u1
ON C.c1 = G.c1
INNER JOIN R
ON P.r1 = R.r1
INNER JOIN F
ON U.f1 = F.f1
RIGHT OUTER JOIN UN
ON U.u1 = UN.u1
然后看起来你的一个人在错误的地方:
FROM P INNER JOIN C
ON P.p1 = C.p1
INNER JOIN G
**ON C.c1 = G.c1**
INNER JOIN U
ON G.u1 = U.u1
INNER JOIN R
ON P.r1 = R.r1
INNER JOIN F
ON U.f1 = F.f1
RIGHT OUTER JOIN UN
ON U.u1 = UN.u1
格式化真的有助于这种事情......