我想读一个看起来完全像这样的字符串:
VPSProtocol=2.22
Status=OK
StatusDetail=0000 : The Authorisation was Successful.
VPSTxId={BBF09A43-913E-14E3-B41B-E5464B6FF8A9}
SecurityKey=EH8VFZUSH9
TxAuthNo=4979698
AVSCV2=SECURITY CODE MATCH ONLY
AddressResult=NOTMATCHED
PostCodeResult=NOTMATCHED
CV2Result=MATCHED
CAVV=AAABARR5kwAAAAAAAAAAAAAAAAA=
3DSecureStatus=OK
...最好进入字典。我已经尝试拆分vbcrlf(我可以向你保证每一行都有一个)和'=',但是不能让它正常运行,经常出现超出界限的错误。任何人都有一些关于如何解决这个问题的奇妙想法?
一如既往地提供帮助。
答案 0 :(得分:1)
您可以使用StringReader:
Dim dic = New Dictionary(Of String, String)
Using reader = New StringReader(someString)
Dim line As String = reader.ReadLine()
While line <> Nothing
Dim tokens = line.Split("=")
If tokens.Length < 2 Then
Continue While
End If
dic.Add(tokens(0), tokens(1))
line = reader.ReadLine()
End While
End Using
答案 1 :(得分:0)
我用这段相当讨厌的代码解决了这个问题;
Dim dictionary As New Dictionary(Of String, String)
Dim x As String = "x?" & Replace(tmp.ToString(), vbCrLf, "&")
Dim arr As String() = x.Split("?".ToCharArray())
If arr.Length >= 2 Then
Dim arr2 As String() = arr(1).Split("&".ToCharArray())
For Each item As String In arr2
Dim arr3 As String() = item.Split("=".ToCharArray())
dictionary.Add(arr3(0), arr3(1))
Next
End If
我希望它可以帮助那里的人,如果有人可以建议改进,请执行:)