Question

此代码触发错误

  query_string := 'SELECT '||dbms_assert.sql_object_name(trim(both ' ' from return_field))|| 
                   ' FROM '||dbms_assert.schema_name(trim(both ' ' from from_schema))||
                        '.'||dbms_assert.sql_object_name(trim(both ' ' from from_table))||  
                  ' WHERE '||dbms_assert.sql_object_name(key_field) || ' = '||key_value;



 EXECUTE IMMEDIATE query_string into return_result;

无效的sql对象。

从文档中我觉得表中的任何对象都是一个sql对象??
什么错了？

考虑在oracle 10g中执行以下功能

在10g上下文中考虑以下函数

    CREATE OR REPLACE FUNCTION scott.tab_lookup (key_field CHAR,
                                       key_value CHAR,
                                       from_schema CHAR,
                                       from_table CHAR,
                                       return_field CHAR,
                                       return_type CHAR)
    RETURN VARCHAR2 IS
    result_a varchar2(1000);
    query_string VARCHAR2(4000);

    /*version 0.5*/
    BEGIN

    query_string := 'SELECT '||dbms_assert.qualified_sql_name(trim(from_table||'.'||return_field))|| 
                       ' FROM '||dbms_assert.schema_name(trim(from_schema))||
                            '.'||dbms_assert.sql_object_name(trim(from_table))||  
                      ' WHERE '||dbms_assert.qualified_sql_name(from_table||'.'||key_field) || ' = '||key_value;

      IF(return_type = 'SQL') THEN
         result_a := query_string;
      ELSE
         EXECUTE IMMEDIATE query_string 
         --USING key_value  
         into result_a;
      END IF;

      RETURN (result_a);
    EXCEPTION 
    WHEN 
        NO_DATA_FOUND THEN 
           RETURN(NULL);
    WHEN
        TOO_MANY_ROWS THEN 
           RETURN('**ERR_DUPLICATE**');
    WHEN OTHERS
    THEN 
    /*
    ORA-44001   INVALID_SCHEMA_NAME 
    ORA-44002   INVALID_OBJECT_NAME
    ORA-44003   INVALID_SQL_NAME
    ORA-44004   INVALID_QUALIFIED_SQL_NAME
    */
        IF    SQLCODE = -44001 THEN 
              RETURN('*ERR_INVALID_SCHEMA*');
        ELSIF SQLCODE = -44002 THEN 
              RETURN('*ERR_INVALID_OBJECT*');
        ELSIF SQLCODE = -44003 THEN 
              RETURN('*ERR_INVALID_SQL_NAME*');
        ELSIF SQLCODE = -44004 THEN 
              RETURN('*ERR_INVALID_QALIFIED_SQLNAME*');
        end if;         
        return ('*ERR_'||sqlcode);
    END;
    /

我正在 ERR_INVALID_OBJECT

--to get the Genrated SQL as Value  

    Select scott.tab_lookup('ID',1,'TEST','TEST_TABLE','TEST_DESC','SQL') from dual;

-- -or-

-- to get the value returned from database field

    Select scott.tab_lookup('ID',1,'TEST','TEST_TABLE','TEST_DESC','') from dual;

我的桌子就像


    TEST_TABLE  
    ====================
    ID   , TEST_DESC
    ====================
    '11' , 'TEST 1'
    '12' , 'TEST 5000'
    '13' , 'TEST INPUT VALUE'
    '14' , 'JUNK VALUE'
    '50' , 'TEST VALUE 50'

此表位于'TEST'架构中，我与SCOTT连接并且SCOTT在TEST.TEST_TABLE上有'GRANT SELECT to scott'

我仍然得到错误

ERR_INVALID_OBJECT

Answer 1

query_string := 'SELECT '||dbms_assert.qualified_sql_name(trim(from_schema||'.'||from_table||'.'||return_field))|| 
                   ' FROM '||dbms_assert.schema_name(trim(from_schema))||
                        '.'||dbms_assert.sql_object_name(trim(from_table))||  
                  ' WHERE '||dbms_assert.qualified_sql_name(from_schema||'.'||from_table||'.'||key_field) || ' = '||key_value;



 EXECUTE IMMEDIATE query_string into return_result;

来自Docs ..

ENQUOTE_LITERAL - 引用字符串文字
ENQUOTE_NAME - 在双q-uotes中包含名称
NOOP - 返回值而不进行任何检查
QUALIFIED_SQL_NAME - 验证输入字符串是否为合格的SQL名称
SCHEMA_NAME - 功能验证输入字符串是否为现有架构名称
SIMPLE_SQL_NAME - 验证输入字符串是否为简单的SQL名称
SQL_OBJECT_NAME - 验证输入参数字符串是否是现有SQL对象的限定SQL标识符

带有DBMS_ASSERT的Oracle SQL注入块

1 个答案: