sql跳过包含字符串的行

Question

您好我需要跳过可能包含文字的行

示例：我有表OUTSTANDING，我的字段在下面给出。

INVOICENO 
AB1       
111
ZX3

我需要跳过包含AB1和ZX3的行，并选择包含111的行

我试过这个查询

"SELECT * FROM [INT]..OUTSTANDING WHERE INVOICENO NOT LIKE '%[a-z,-]%'";

Answer 1

尝试：

"SELECT * FROM [INT]..OUTSTANDING WHERE NOT INVOICENO LIKE '%[0-9]%'";

或

...where INVOICENO not like '%[a-z]%'

除非需要更高级的正则表达式....
来源：http://www.sqllion.com/2010/12/pattern-matching-regex-in-t-sql/

Answer 2

Select *
FROM [INT]..OUTSTANDING 
WHERE IsNumeric(INVOICENO ) = 1 
And INVOICENO Is Not NULL

Answer 3

WHERE ISNUMERIC(INVOICENO) = 1

http://technet.microsoft.com/en-us/library/ms186272.aspx

Answer 4

尝试以下方法：

方法1：

SELECT * 
FROM [INT]..OUTSTANDING
WHERE InvoiceNo IS NOT NULL
    AND ISNUMERIC(InvoiceNo)=1

方法2：

SELECT * 
FROM [INT]..OUTSTANDING 
WHERE InvoiceNo IS NOT NULL
  AND INVOICENO NOT LIKE '%[^0-9]%'