Question

我认为这不是应该但我面临着这些问题。我正在研究核心日期，在获取它之后我正试图将其保存到nsarray中。但每次数据库中的最后数据都保存到数组中。我希望每个数据都插入到数据库中。假设我有一个属性名称account_name 我添加了A，B，C，X，Y，Z。在这段代码中，我只是在我的数组中得到最后一个值Z. :( 但是当我打印它然后我得到所有数据.. 任何解决方案？

NSArray *fetchedObjects; 
AppDelegate *delegate = [UIApplication sharedApplication].delegate;
NSManagedObjectContext *context = [delegate managedObjectContext];
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:@"Chart_of_Accounting" inManagedObjectContext:context];
[fetchRequest setEntity:entity];

NSError *error;
fetchedObjects = [context executeFetchRequest:fetchRequest error:&error];

for (NSManagedObject *obj in fetchedObjects) {
    debitArray = [NSMutableArray arrayWithObject:[obj valueForKey:@"account_name"]];
    creditArray = [NSMutableArray arrayWithObject:[obj valueForKey:@"account_name"]];
    NSLog(@"Account Name: %@", [obj valueForKey:@"account_name"]);
}

Answer 1

试试这个

NSArray *fetchedObjects; 
AppDelegate *delegate = [UIApplication sharedApplication].delegate;
NSManagedObjectContext *context = [delegate managedObjectContext];
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:@"Chart_of_Accounting" inManagedObjectContext:context];
[fetchRequest setEntity:entity];

NSError *error;
fetchedObjects = [context executeFetchRequest:fetchRequest error:&error];
NSMutableArray *debitArray = [[NSMutableArray alloc] init];
NSMutableArray *creditArray = [[NSMutableArray alloc] init];
for (NSManagedObject *obj in fetchedObjects) {
    [debitArray addObject:[obj valueForKey:@"account_name"]];
    [creditArray addObject:[obj valueForKey:@"account_name"]];
    NSLog(@"Account Name: %@", [obj valueForKey:@"account_name"]);
}

Answer 2

因为，每次初始化。使用addObject

debitArray = creditArray = [[NSMutableArray alloc] init];
for (NSManagedObject *obj in fetchedObjects) {
    [debitArray addObject:[obj valueForKey:@"account_name"]];
    [creditArray addObject:[obj valueForKey:@"account_name"]];

}NSLog(@"Account Name: %@", [obj valueForKey:@"account_name"]);

Answer 3

在你的循环中：

for (NSManagedObject *obj in fetchedObjects) {
   debitArray = [NSMutableArray arrayWithObject:[obj valueForKey:@"account_name"]];
   creditArray = [NSMutableArray arrayWithObject:[obj valueForKey:@"account_name"]];
   NSLog(@"Account Name: %@", [obj valueForKey:@"account_name"]);
}

每次都要实例化一个新数组（并覆盖前一个数组）。这解释了发生了什么。

你应该在循环之外实例化数组，然后在循环中将对象添加到它。

debitArray = [NSMutableArray arrayWithCapacity:[fetchedObjects count]];
creditArray = [NSMutableArray arrayWithCapacity:[fetchedObjects count]];

for (NSManagedObject *obj in fetchedObjects) {

   [debitArray addObject:[obj valueForKey:@"account_name"]];
   [creditArray addObject:[obj valueForKey:@"account_name"]];
   NSLog(@"Account Name: %@", [obj valueForKey:@"account_name"]);

}

Answer 4

不要在不同的数组中创建重复值。

将您的fetchedObjects数据作为NSArray Type返回，然后从coredata返回。

fetchedObjects=[self yourRetriveMethod];

    for (NSManagedObject *obj in fetchedObjects) {
        debitArray = [NSMutableArray arrayWithObject:[obj valueForKey:@"account_name"]];
        creditArray = [NSMutableArray arrayWithObject:[obj valueForKey:@"account_name"]];
        NSLog(@"Account Name: %@", [obj valueForKey:@"account_name"]);
    }

获取核心数据并将其保存到nsarray

4 个答案: