Question

这有效：

XAML：

<Window x:Class="Test239992.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Window1" Height="300" Width="300">
    <StackPanel>
        <TextBlock Tag="1" Text="Customers" MouseDown="Handle_Click"/>
        <TextBlock Tag="2" Text="Appointments" MouseDown="Handle_Click"/>
    </StackPanel>
</Window>

代码背后：

using System;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Input;

namespace Test239992
{
    public partial class Window1 : Window
    {
        public Window1()
        {
            InitializeComponent();
        }

        private void Handle_Click(object sender, MouseButtonEventArgs e)
        {
            int id = Int32.Parse(((TextBlock)sender).Tag.ToString());
            MessageBox.Show("you chose id " + id.ToString());
        }
    }
}

但如何将MouseDown事件置于样式中，这会给我错误“无法在类型'System.Windows上找到样式属性'MouseDown' .Controls.TextBlock'“：

<Window x:Class="Test239992.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Window1" Height="300" Width="300">
    <Window.Resources>
        <Style TargetType="{x:Type TextBlock}" x:Key="ClickableTextBlockStyle">
            <Setter Property="MouseDown" Value="Handle_Click" />
        </Style>
    </Window.Resources>
    <StackPanel>
        <TextBlock Tag="1" Text="Customers" Style="{DynamicResource ClickableTextBlockStyle}"/>
        <TextBlock Tag="2" Text="Appointments" Style="{DynamicResource ClickableTextBlockStyle}"/>
    </StackPanel>
</Window>

Answer 1

尝试EventSetter：）

    <Style TargetType="{x:Type TextBlock}" x:Key="ClickableTextBlockStyle">
        <EventSetter Event="MouseDown" Handler="Handle_Click" />
    </Style>

Answer 2

查看WPF中的触发器：
http://mark-dot-net.blogspot.com/2007/07/creating-custom-wpf-button-template-in.html

如何将MouseDown事件放入样式中？

2 个答案: