Question

我在.sh文件中定义了一个数组，如下所示：

hosts=(NODE IPS)
hosts[0]="1.110,Node-01"
hosts[1]="1.111,Node-02"
hosts[2]="1.112,Node-03"
hosts[3]="1.113,Node-04"
hosts[4]="1.114,Node-05"
hosts[5]="1.115,Node-06"

如何循环遍历数组，但是根据commma拆分每个索引，并将值存储在变量中，如下所示：

for index in ${!hosts[*]}
do
    ip = ## some way to split the string, and get the left side of the index
    hostname = ## some way to split the string, and get the right side of the index
    ## do something with the above variables
    echo "IP: $ip HOSTNAME: $hostname"
done

如果这有帮助，我正在使用linux

Answer 1

for host in "${hosts[@]}"; do
    IFS=, read ip hostname <<< "$host"
    echo "IP: $ip, HOSTNAME: $hostname"
done

Answer 2

试试这个-->

使用tr打破字符串

for w in $(echo "hello/Hi/Bye" | tr "/" " ") ; do echo $w; done

输出

Hello
Hi
Bye

2 。可以使用awk声明。示例---> 使用“：”作为以下示例的分隔符

$ echo "abc:def" | awk -F':' '{print "field1: "$1 "\nfield2: "$2}'

输出

field1: abc
field2: def

如何在bash中基于分隔符拆分字符串？

2 个答案: