Question

我有以下表格结构 - 例如Users，Projects。

用户has_many项目项目has_many照片

但我想将项目和照片的某些基本内容嵌入到用户表中，这样我就可以减少某些页面的数据库调用次数。

以下是我提出的结构。

用户表

[
  {
    "id": "LONG-MONGO-ID-HERE-USER-1",
    "name": "Harsha MV",
    "email": "harsha@mink7.com",
    "gender": "male",
    "telephone": "9986377561",
    "is_pro": 1,
    "projects": [
      {
        "id": "LONG-MONGO-ID-HERE-PROJECT-1",
        "name": "Nike",
        "url": "http://nike.com",
        "logo": "logo_nike.jpg",
        "photos": [
          {
            "title": "Some title for an Image",
            "file": "project1_photo1.jpg"
          },
          {
            "title": "another title for an Image",
            "file": "project1_photo2.jpg"
          }
        ]
      },
      {
        "id": "LONG-MONGO-ID-HERE-PROJECT-2",
        "name": "BMW",
        "url": "http://bmw.com",
        "logo": "logo_bmw.jpg",
        "photos": [
          {
            "title": "Some title for an Image",
            "file": "project2_photo1.jpg"
          },
          {
            "title": "another title for an Image",
            "file": "project2_photo2.jpg"
          }
        ]
      }
    ]
  },
  {
    "id": "LONG-MONGO-ID-HERE-USER-2",
    "name": "Pruthvi Gowda",
    "email": "pruthvi@mink7.com",
    "gender": "male",
    "telephone": "9982318016",
    "is_pro": 0,
    "projects": [
      {
        "id": "LONG-MONGO-ID-HERE-PROJECT-3",
        "name": "Adidas",
        "url": "http://adidas.com",
        "logo": "logo_adidas.jpg",
        "photos": [
          {
            "title": "Some title for an Image",
            "file": "project1_photo3.jpg"
          },
          {
            "title": "another title for an Image",
            "file": "project1_photo4.jpg"
          }
        ]
      },
      {
        "id": "LONG-MONGO-ID-HERE-PROJECT-2",
        "name": "BMW",
        "url": "http://bmw.com",
        "logo": "logo_bmw.jpg",
        "photos": [
          {
            "title": "Some title for an Image",
            "file": "project2_photo1.jpg"
          },
          {
            "title": "another title for an Image",
            "file": "project2_photo2.jpg"
          }
        ]
      }
    ]
  }
]

项目表

[
    {
      "id": "LONG-MONGO-ID-HERE-PROJECT-1",
      "name": "Nike",
      "url": "http://nike.com",
      "logo": "logo_nike.jpg",
      "about": "Lorem Ipsum is simply dummy text of the printing and typesetting industry.",
      "testimonial": "e middle of text. All the Lorem Ipsum generators on the Internet tend",
      "photos": [
        {
          "title": "Some title for an Image",
          "description": "um is simply dummy text of the printing and t",
          "file": "project1_photo1.jpg"
        },
        {
          "title": "another title for an Image",
          "description": "text of the printing and t um is simply dummy",
          "file": "project1_photo2.jpg"
        }
      ],
      "user": {
        "id": "LONG-MONGO-ID-HERE-USER-1",
        "name": "Harsha MV",
        "email": "harsha@mink7.com"
      }
    },
    {
      "id": "LONG-MONGO-ID-HERE-PROJECT-2",
      "name": "BMW",
      "url": "http://bmw.com",
      "logo": "logo_bmw.jpg",
      "about": "It is a long established fact that a reader will be distracted by the",
      "testimonial": "from sections 1.10.32 and 1.10.33 of de Finibus Bonorum et Malorum",
      "photos": [
        {
          "title": "Some title for an Image",
          "description": "um is simply dummy text of the printing and t",
          "file": "project2_photo1.jpg"
        },
        {
          "title": "another title for an Image",
          "description": "text of the printing and t um is simply dummy",
          "file": "project2_photo2.jpg"
        }
      ],
      "user": {
        "id": "LONG-MONGO-ID-HERE-USER-1",
        "name": "Harsha MV",
        "email": "harsha@mink7.com"
      }
    }
  ]

据我所知，MongoDb完全是关于数据的复制。这是设计数据库结构的正确方法。

class User
  include Mongoid::Document

  field :first_name, type: String
  field :last_name, type: String
  field :company_name, type: String


  embeds_many :projects, class_name: "Project"
  has_many :projects, class_name: "Project"

end

我可以做上面这样的事情，这样我就可以保存两个相同数据的实例。但正如您在嵌入式文档中看到的那样，我没有存储项目中的所有数据 - 如何将所有数据作为嵌入文档添加但是作为单独的表存储呢？

Answer 1

无法为嵌入和引用的集合添加相同的模型。您可以通过引用用户中的项目集合将结构与最初提到的结构相同。

创建虚拟模型说ImportantProject，它将嵌入到用户中，您可以在数据库中进行更改时同步此模型中的数据项目。

Rails MongoDb has_many和embeds_many

1 个答案: