Question

我正在尝试为我的（快速接近的）婚礼编写我认为非常简单的PHP RSVP页面。我正在专门为这项任务学习PHP，一切都很顺利，直到我碰壁。下面是我设想这个工作的高级步骤，以及我目前编写的代码。我真的很想在本周完成这项工作，所以任何帮助都会非常感激。

用户输入姓氏并点击“搜索”按钮。 Here是表单形状的图像。下面是表单的HTML。

        <form method = "post" action="rsvp.php">
            <span>First Name:</span><input type="text" name="firstName" value="Father">
            <span>Last Name </span><input type="text" name="lastName" value="Test">
            <input type="submit" name="search_submit" value="Search">
        </form>

在“搜索”按钮上按，查询数据库。下面是PHP代码。

        if (isset($_POST['search_submit'])) {
            //Connect to the appropriate database.
            include 'dbconnect.php';
            //Set variables.
            $firstName = $_POST["firstName"];
            $lastName = $_POST["lastName"];
            $query = "SELECT * FROM guests WHERE PartyID IN (SELECT PartyID FROM guests WHERE FirstName = '$firstName' AND LastName = '$lastName')";
            $result = mysqli_query($sql, $query);
            //If query doesn't return any results, give an error.
            if (mysqli_num_rows($result) == 0) {
                echo "<p id=" . '"' . "searchError" . '"' . ">Sorry, I couldn't find your name.  Try again.  If you still have an issue please send me an email.";
            } 
            //If query does return results, create a new form that allows guests to say if they are attending or not.
            else {
                echo '<form method = "post" action="rsvp.php">
                <span class="guestNames">Party Members</span>
                <span class="radioButtons">Attending</span>
                <span class="radioButtons">Not Attending</span>
                <br/>
                <br/>
                ';
                while ($row = mysqli_fetch_array($result)) {
                    echo '<span class="guestNames">' . $row['FirstName']
                    . ' '
                    . $row['LastName'] . '</span>
                     <input type="radio" class="radioButtons" name="' . $row['ID'] . '"value="yes">
                     <input type="radio" class="radioButtons" name="' . $row['ID'] . '"value="no"> 
                    <br />
                    ';
                }
                echo '<input type="submit" name="rsvp_submit" value="RSVP">
                </form>';
            }

            mysqli_close($sql);
        }

创建另一个表单。数据库返回用户方的所有成员的名称，以及“出席”或“不出席”的单选按钮选项。它看起来像this。

用户为每个成员选择合适的单选按钮并点击“RSVP”按钮。这是我被困的地方。见下文......

            //This is the code that will eventually update the SQL database with the user's responses.
            if (isset($_POST['rsvp_submit'])) {
                echo 'What do I do now?';
            }

按“RSVP”按钮，按每个来宾运行相应的更新声明。

我真的认为我可以弄清楚所有数据验证（确保每个客户都选择了一个无线电盒）并在我越过第4步后更新语句。我真的不知道如何处理这个问题。我对应该做什么有很多想法，但不是比我现有的更长时间，我希望我能从这里的专家那里得到一些想法。再次，非常感谢任何帮助。

Answer 1

我认为你的表格应该是：

<input type="radio" class="radioButtons" name="guess[' . $row['ID'] . ']" value="yes">
<input type="radio" class="radioButtons" name="guess[' . $row['ID'] . ']" value="no">

然后，在你的php文件中：

if (isset($_POST['rsvp_submit'])) {
    foreach ($_POST['guess'] as $key => $value) {
         $attending = 0;
         $not_attending = 0;
         if ($value == 'yes') {
             $attending = 1;
         } else if ($value == 'no') {
             $not_attending = 1;
         }
         $sql = 'UPDATE guess set attending = $attending, not_attending = $not_attending WHERE id = $key;
         .....
    }
}

简单的PHP RSVP表单

1 个答案: