我正在尝试从我的Galaxy SII向我的计算机上的数据库做一个基本请求,该数据库有一个wamp设置。
应用程序在手机上崩溃并关闭。我认为它是在httpPost上进行的,因为在apache服务器的访问日志中没有显示任何内容。 (通过我的手机浏览器可以正常运行Web服务)。我在Eclipse中的logCat中获得了NullPointerExeptions。
查找信息一段时间后,我不知道我应该通过Android应用程序获取json结果。我认为下面的代码实际上就是你需要的,给予或采取一些小的改动。
有什么我可以改变我的代码或者我应该丢弃它并尝试不同的方法吗?
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
String result = null;
InputStream is = null;
StringBuilder sb=null;
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.1.1.11/food/food.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection"+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line="0";
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
//paring data
int fd_id = 0;
String fd_name = null;
JSONArray jArray = new JSONArray();
try{
jArray = new JSONArray(result);
JSONObject json_data=null;
for(int i=0;i<jArray.length();i++){
json_data = jArray.getJSONObject(i);
fd_id=json_data.getInt("FOOD_ID");
fd_name=json_data.getString("FOOD_NAME");
}
}catch(JSONException e1){
Toast.makeText(getBaseContext(), "No Food Found", Toast.LENGTH_LONG).show();
}catch (ParseException e1){
e1.printStackTrace();
}
Toast.makeText(getBaseContext(), fd_name, Toast.LENGTH_LONG).show();
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
}
答案 0 :(得分:0)
您永远不应该从应用程序线程进行网络调用。您需要将网络调用放在Service,Thread或AsyncTask中。
答案 1 :(得分:0)
你应该像这样的asynctask进行网络通信:
class talkToServer extends AsyncTask<Void, Void, String>{
@Override
protected String doInBackground(Void... params) {
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.1.1.11/food/food.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection"+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line="0";
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
//paring data
int fd_id = 0;
String fd_name = null;
JSONArray jArray = new JSONArray();
try{
jArray = new JSONArray(result);
JSONObject json_data=null;
for(int i=0;i<jArray.length();i++){
json_data = jArray.getJSONObject(i);
fd_id=json_data.getInt("FOOD_ID");
fd_name=json_data.getString("FOOD_NAME");
}
}catch(JSONException e1){
Toast.makeText(getBaseContext(), "No Food Found", Toast.LENGTH_LONG).show();
}catch (ParseException e1){
e1.printStackTrace();
}
return fd_name;
}
@Override
public void onPostExecute(String temp){
Toast.makeText(getBaseContext(), temp, Toast.LENGTH_LONG).show();
}
}