Question

我正在为mp3和mp4制作一个下载程序，我想在php中有两个php文件，两个按钮调用两个php文件但只有第一个php文件可以工作。

popup.php的代码

<?php
    include "downloadmp3.php";
    include "downloadmp4.php";
?>
<html>
<head></head>
<body bgcolor="#E6E6E6">
    <form method="post">
        <label for="url">Download mp3:</label>
        <input type="text" name="url" value="" id="url">
        <input type="submit" name="submit" value="Download">
        <hr>
    </form>
    <form method="post">
        <label for="url1">Download mp4:</label>
        <input type="text" name="url1" value="" id="url1">
        <input type="submit" name="submit" value="Download">
    </form>
</body>
</html>

downloadmp3.php的代码

<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST'){
    $url = (isset($_POST['url']) && !empty($_POST['url'])) ? $_POST['url'] : false;
    if (!$url) {
        echo "Vul alstublieft een url in";
    } else {
        $source = file_get_contents($url);
        $source = urldecode($source);

        // Verkrijg de video titel.
        $vTitle_results_1 = explode('<title>', $source);
        $vTitle_results_2 = explode('</title>', $vTitle_results_1[1]);

        $title = trim(str_replace(' – YouTube', ”, trim($vTitle_results_2[0])));

        // Extract video download URL.
        $dURL_results_1 = explode('url_encoded_fmt_stream_map', "url=", $source);
        $dURL_results_2 = explode('\u0026quality', $dURL_results_1[1]);

        // Force download van d  video.
        $file = str_replace(' ', '_', strtolower($title)).'.mp4';

        header("Cache-Control: public");
        header("Content-Description: File Transfer");
        header("Content-Disposition: attachment; filename=$file");
        header("Content-Type: video/mp4");
        header("Content-Transfer-Encoding: binary");

        readfile($dURL_results_2[0]);

        exit;
    }
}
?>

和downloadmp4.php的代码

<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST'){
    $url = (isset($_POST['url1']) && !empty($_POST['url1'])) ? $_POST['url1'] : false;
    if (!$url) {
        echo "Vul alstublieft een url in";
    } else {
        $source = file_get_contents($url);
        $source = urldecode($source);

        // Verkrijg de video titel.
        $vTitle_results_1 = explode('<title>', $source);
        $vTitle_results_2 = explode('</title>', $vTitle_results_1[1]);

        $title = trim(str_replace(' – YouTube', ”, trim($vTitle_results_2[0])));

        // Extract video download URL.
        $dURL_results_1 = explode('url_encoded_fmt_stream_map', "url1=", $source);
        $dURL_results_2 = explode('\u0026quality', $dURL_results_1[1]);

        // Force download van d  video.
        $file = str_replace(' ', '_', strtolower($title)).'.mp4';

        header("Cache-Control: public");
        header("Content-Description: File Transfer");
        header("Content-Disposition: attachment; filename=$file");
        header("Content-Type: video/mp4");
        header("Content-Transfer-Encoding: binary");

        readfile($dURL_results_2[0]);

        exit;
    }
}
?>

更新提交MP3表格的表格有效。但是为MP4提交的表单不起作用。请提供一个解决方案，使其工作。

Answer 1

只有第一个php文件调用正在运行，因为以下条件：

if ($_SERVER['REQUEST_METHOD'] == 'POST'){

由于首先包含了downloadmp3.php，因此if condition正在给出结果。使用适当的表单处理程序使其工作。最佳做法是为表单使用唯一的名称。

Answer 2

此代码在所有浏览器中都能正常使用，下载的文件效果很好：下载audio.php

    <?php
    $file = $_GET['file'];
    header ('Content-type: octet/stream');
    header ('Content-disposition: attachment; filename='.$file.';');
    header('Content-Length: '.filesize($file));
    readfile($file);
    exit;
    ?>

的test.html

    <a href='download-audio.php?file=duetsong.mp3'>Download Duet song MP3</a>
    <a href='download-audio.php?file=duetsong.mp4'>Download Duet song MP4</a>

使用PHP下载MP3和MP4文件

2 个答案: