解析错误：语法错误，意外'$ password'（T_VARIABLE）

Question

我检查了一切。它仍然不起作用，当我在第6行中添加分号（;）时说

Parse error: syntax error, unexpected ';' in line 6

我该怎么办？这是我的代码：

<?php

if(isset($_POST['logintoadminpanel']))
(   

    include_once 'connection.php';

    $username = $_POST['username'];
    $password = $_POST['password'];


    if(empty($username) || empty($password))
    (
        echo "Please fill the required fields";
    )
)
?>

Answer 1

你正在使用parens for blocks。你需要使用大括号。

if (...)
{
   ...
}

Answer 2

对if条件使用{}而不是（）。

<?php

if(isset($_POST['logintoadminpanel']))
{

    include_once 'connection.php';

    $username = $_POST['username'];
    $password = $_POST['password'];


    if(empty($username) || empty($password))
    {
        echo "Please fill the required fields";
    }
}
?>

Answer 3

Please check below tested code.. 

<?php

if(isset($_POST['logintoadminpanel']))
{

    include_once ('connection.php');

    $username = $_POST['username'];
    $password = $_POST['password'];


    if(empty($username) || empty($password))
    {
        echo "Please fill the required fields";
    }
}
?>