Question

如果有人可以提供以下建议，我会很感激：我的表看起来像这样：

ID    SEQ   ACCOUNT  AMOUNT   DESCRIPTION           ...          ....
0719  1     8019     222,2    this is the
0719  1     NULL     NULL     description of
0719  1     NULL     NULL     account with
0719  1     NULL     NULL     amount= 222,2
0719  1     NULL     NULL     NULL
0719  1     NULL     NULL     NULL
0719  2     8019     111,1    this is the
0719  2     NULL     NULL     description of
0719  2     NULL     NULL     account with
0719  2     NULL     NULL     amount= 111,1

正如您所看到的，有一个ID和一个ACCOUNT，其中包含多个AMOUNTS。我需要合并DESCRIPTION列分组的每个条目的SEQ。

我的目标是：

ID    SEQ   ACCOUNT  AMOUNT   DESCRIPTION         ...           ...
0719  1     8019     222,2    this is the description of account with amount= 222,2
0719  2     8019     111,1    this is the description of account with amount= 111,1

我尝试使用COALESCE或FOR XML运算符，但无法在SEQ处添加分组：

DECLARE @Desc NVARCHAR(8000) 
SELECT @Desc = COALESCE(@Desc + ', ', '') + [DESCRIPTION]
FROM [TABLE]
WHERE MDC_ID = '0719'
      AND (ACCOUNT = '8019' or ACCOUNT IS NULL) 
      AND (AMOUNT= 222,2 OR AMOUNT is null)    
--GROUP BY SEQ -- DESCRIPTION is invalid in the select list because it is not contained in 
                --either an aggregate function or the GROUP BY clause
SELECT @Desc

如何更改脚本？

Answer 1

试试这个：

SELECT T.ID, T.SEQ, MAX(T.AMOUNT) AMOUNT, D.DS
FROM tbl T
CROSS APPLY
(
    SELECT [DESCRIPTION] + ' '
    FROM tbl B
        WHERE T.ID = B.ID
            AND T.SEQ = B.SEQ
            AND [DESCRIPTION] IS NOT NULL
    FOR XML PATH('')
) D(DS)
GROUP BY ID, SEQ, DS

<强> SQL FIDDLE DEMO

Answer 2

SELECT id, seq, MAX(account),MAX(amount),
(SELECT DESCRIPTION+' ' FROM yourtable b WHERE b.id=a.id AND b.seq=a.seq FOR XML PATH(''))
FROM yourtable a
GROUP BY id, seq

在T-SQL中使用分组将几个行连接成一个

2 个答案: