Question

从下面的json数据我怎样才能获得address: '172.16.2.18'

我只想从以下josn数据中获取172.16.2.18。如何可能？

{
    'Local Area Connection': [{
        address: 'fe80::c1c6:e78a:ece:435',
        family: 'IPv6',
        internal: false
    }, {
        address: '172.16.2.18',
        family: 'IPv4',
        internal: false
    }],
    'VMware Network Adapter VMnet1': [{
            address: 'fe80::55d6:5243:74eb:ec58',
            family: 'IPv6',
            internal: false
        }, {
            address: '169.254.236.88',
            family: 'IPv4',
            internal: false
        }
        'VMware Network Adapter VMnet8': [{
                address: 'fe80::a50c:fc9f:921a:7a22',
                family: 'IPv6',
                internal: false
            }, {
                address: '169.254.122.34',
                family: 'IPv4',
                internal: false
            }
            'Loopback Pseudo-Interface 1': [{
                address: '::1',
                family: 'IPv6',
                internal: true
            }, {
                address: '127.0.0.1',
                family: 'IPv4',
                internal: true
            }]
        }

Answer 1

您的json数据中有几个语法错误*，但一旦纠正，您可以使用以下命令访问该元素：

var address = jsonData["Local Area Connection"][1].address;

实例：http://jsfiddle.net/VBKvZ/

_{*在每个“适配器列表”}

之后，语法错误缺少关闭数组和逗号（],）

从json数据中获取特定值

1 个答案: