Question

note:
 {"category_id":"1","name":"Notes","icon":"images\/note.png"},
quote:
 {"category_id":"2","name":"Quotes","icon":"images\/quote.png"},
project:
 {"category_id":"3","name":"Projects","icon":"images\/project.png"},
skill:
 {"category_id":"4","name":"Skills","icon":"images\/skill.png"}

这是我的控制台中显示的内容。我已将json_decode用于我的查询，并与字符串连接，我相信这是问题的原因。

那么如何将字符串数据转换为json格式呢？

Answer 1

如果那是字符串，那么我建议将其包装在{ ... }中并使用`JSON.parse。即：

var json = JSON.parse('{' + string + '}');

当然，您需要将JSON lib帮助器添加到页面https://github.com/douglascrockford/JSON-js

Answer 2

你可以使用JSON.parse(string)这将从你的字符串中返回一个JSON

Answer 3

我认为你的PHP有问题而不是Javascript：

你已经解码了一个JSON字符串，用于在json_decode处理它的PHP对象中对其进行转换...但现在你必须以格式良好的JSON字符串取回它。

但首先你的字符串无效，对于JSON标准（在PHP中）：

将您的字符串括在 {
必须将{strong>注释，引用，项目，技能的名称封装在"内，你的新字符串：

{ “注意”：{ “CATEGORY_ID”： “1”， “名称”： “注释”， “图标”： “图像/ note.png”}， “引用”：{ “CATEGORY_ID”： “2”， “名称”： “报价”， “图标”： “图像/ quote.png”}， “项目”{ “CATEGORY_ID”： “3”， “名”： “项目”， “图标”： “图像/ project.png”}， “技能”：{ “CATEGORY_ID”： “4”， “名称”： “技能”， “图标”： “图像/ skill.png”} }

现在在PHP中看到这个JSON编码的例子：

$yourString = '{"note":{"category_id":"1","name":"Notes","icon":"images\/note.png"},"quote":{"category_id":"2","name":"Quotes","icon":"images\/quote.png"},"project":{"category_id":"3","name":"Projects","icon":"images\/project.png"},"skill":{"category_id":"4","name":"Skills","icon":"images\/skill.png"}}'; 
$JSON_FOR_PHP = json_decode($yourString);
$JSON_FOR_JS = json_encode($JSON_FOR_PHP);

/* response: */
echo "JSON for PHP (associative Array):<br><br>";
var_dump($JSON_FOR_PHP);
echo"<br><br>";
echo "JSON for JAVASCRIPT (JSON string {add content type: application/json}):<br><br>";
echo $JSON_FOR_JS;

响应：

JSON for PHP (associative Array):

object(stdClass)#1 (4) { ["note"]=> object(stdClass)#2 (3) { ["category_id"]=> string(1) "1" ["name"]=> string(5) "Notes" ["icon"]=> string(15) "images/note.png" } ["quote"]=> object(stdClass)#3 (3) { ["category_id"]=> string(1) "2" ["name"]=> string(6) "Quotes" ["icon"]=> string(16) "images/quote.png" } ["project"]=> object(stdClass)#4 (3) { ["category_id"]=> string(1) "3" ["name"]=> string(8) "Projects" ["icon"]=> string(18) "images/project.png" } ["skill"]=> object(stdClass)#5 (3) { ["category_id"]=> string(1) "4" ["name"]=> string(6) "Skills" ["icon"]=> string(16) "images/skill.png" } }

JSON for JAVASCRIPT (JSON string {add content type: text/json}):

{"note":{"category_id":"1","name":"Notes","icon":"images\/note.png"},"quote":{"category_id":"2","name":"Quotes","icon":"images\/quote.png"},"project":{"category_id":"3","name":"Projects","icon":"images\/project.png"},"skill":{"category_id":"4","name":"Skills","icon":"images\/skill.png"}}

如果您只回显$JSON_FOR_JS并将内容类型更改为 application / json ，则会得到响应是一个有效的JSON字符串，您可以在javascript中使用JSON.parse()进行解析：< / p>

header('Content-Type: application/json');
echo $JSON_FOR_JS;

或直接在JS脚本（html页面或.js文件中没有脚本标记）中回显：

现在在javascript中你有一个带有字符串内容的对象js_json。

将字符串数据转换为json格式

3 个答案: